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Serhud [2]
3 years ago
10

Triangle P Q R is shown. The length of P Q is 20 and the length of P R is 12. Angle Q P R is 68 degrees and angle P Q R is 36 de

grees. Trigonometric area formula: Area = One-half a b sine (C) What is the area of triangle PQR? Round to the nearest tenth of a square unit.

Mathematics
1 answer:
Tom [10]3 years ago
3 0

Answer:

<h2> 112.3 square units</h2>

Step-by-step explanation:

Find the sketch of the triangle attached.

Area of the triangle = \frac{1}{2}|PQ| |PR| sinQPR

Given PQ = 20, PR = 12 and ∠QPR = 68°

Area of the triangle = 1/2 * 20 * 12 * sin68°

Area of the triangle = 120sin68°

Area of the triangle = 112.26 square units

Area of the triangle ≈ 112.3 square units (to the nearest tenth of a square unit)

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levacccp [35]

Answer:

3.2h+1.6

Step-by-step explanation:

3h-2(-0.1h-0.8)

3h+0.2h+1.6

3.2h+1.6

8 0
3 years ago
The nutritional chart on the side of a box of a cereal states that there are 87 calories in a 3/4 cup serving. How many calories
alexira [117]

Answer:

Total calories in 8 cup = 928 calories

Step-by-step explanation:

Given:

Calories in 3/4 cup of cereal = 87 calories

Find:

Total calories in 8 cup

Computation:

Total calories in 8 cup = 8 x 87 x [4/3]

Total calories in 8 cup = 928 calories

6 0
3 years ago
The simple interest on a certain sum of money for 2 years at 5% per annum is Rs 320. What will be the compound interest on the s
Brilliant_brown [7]

Answer:

Rs 328

Step-by-step explanation:

Find the <u>principal</u> amount invested.

<u>Simple Interest Formula</u>

I = Prt

where:

  • I = interest earned
  • P = principal
  • r = interest rate (in decimal form)
  • t = time (in years)

Given:

  • I = Rs 320
  • r = 5% = 0.05
  • t = 2 years

Substitute the given values into the formula and solve for P:

⇒ 320 = P(0.05)(2)

⇒ 320 = P(0.1)

⇒ P = 3200

<u>Compound Interest Formula</u>

\large \text{$ \sf I=P\left(1+\frac{r}{n}\right)^{nt} -P$}

where:

  • I = interest earned
  • P = principal amount
  • r = interest rate (in decimal form)
  • n = number of times interest applied per time period
  • t = number of time periods elapsed

Given:

  • P = 3200
  • r = 5% = 0.05
  • n = 1 (annually)
  • t = 2 years

Substitute the given values into the formula and solve for I:

\implies \sf I=3200\left(1+\frac{0.05}{1}\right)^{2} -3200

\implies \sf I=3200\left(1.05\right)^{2} -3200

\implies \sf I=3200\left(1.1025\right) -3200

\implies \sf I=3528-3200

\implies \sf I=328

Therefore, the compound interest on the same sum for the same time at the same rate is Rs 328.

7 0
2 years ago
8+(3+4) rewrite using the associative property
Goshia [24]
The Associative Property allows you to "regroup" addition and multiplication problems. You can group this problem in two other ways,
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8 0
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dybincka [34]

Answer:

0.375

Step-by-step explanation:

0.6875-0.3125 = 0.375

8 0
2 years ago
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