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Serhud [2]
3 years ago
10

Triangle P Q R is shown. The length of P Q is 20 and the length of P R is 12. Angle Q P R is 68 degrees and angle P Q R is 36 de

grees. Trigonometric area formula: Area = One-half a b sine (C) What is the area of triangle PQR? Round to the nearest tenth of a square unit.

Mathematics
1 answer:
Tom [10]3 years ago
3 0

Answer:

<h2> 112.3 square units</h2>

Step-by-step explanation:

Find the sketch of the triangle attached.

Area of the triangle = \frac{1}{2}|PQ| |PR| sinQPR

Given PQ = 20, PR = 12 and ∠QPR = 68°

Area of the triangle = 1/2 * 20 * 12 * sin68°

Area of the triangle = 120sin68°

Area of the triangle = 112.26 square units

Area of the triangle ≈ 112.3 square units (to the nearest tenth of a square unit)

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