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Inga [223]
2 years ago
13

A mealworm crawled 2.1 meters in 6 minutes. At this rate, how many meters did the mealworm crawl in 1 minute

Mathematics
1 answer:
lubasha [3.4K]2 years ago
8 0

Answer:

at this rate

mealworm crawl 0.35 m in 1 minute

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When you roast coffee, it loses 12% of its weight. how much fresh coffee do you need in order to get 14 2/25 lb of roasted coffe
Komok [63]

Answer:

16 lb of fresh coffee.

Step-by-step explanation:

Let  x pound be the  amount of fresh coffee needed.

100 - 12 = 88%  is equivalent to 14 2/25  of roasted coffee.

By proportion  x = 14 2/25  /  88/100

= 352 / 25 * 100/88

= 35200 / 25 * 88

= 16 lb  (answer).

6 0
3 years ago
In a certain clothing store,6 shirts and 3 ties cost $79.50 ,and 3 shirts and 2 ties cost $41. determine the cost of each shirt.
Komok [63]

Answer:

Each shirt cost $12

Step-by-step explanation:

First, we have to interpret this question and turn each to an equation, letting shirts represent the letter s and ties represent the letter t.

6 shirts and 3 ties cost $79.50 would be interpreted to 6s+3t=79.5 ,and 3 shirts and 2 ties cost $41 would be interpreted to 3s+2t=41

Hence we have two equations, and we solve them simultaneously.

6s+3t=79.5 (Equation 1)

3s+2t=41 (Equation 2)

We can either use the substitution method or the elimination method but for the sake of this question, we use the Elimination method.

6s+3t=79.5 (Equation 1)

3s+2t=41 (Equation 2)

We multiply equation 1 by 2 and we multiply equation 2 by 3, I'm prefer to eliminate the

2(6s+3t=79.5)

12s+6t=159 Equation 3

3(3s+2t=41)

9s+6t=123 Equation 4

We subtract equation 4 from equation 3.

12s+6t=159

9s+6t=123

12s-9s=3s

6t-6t=0

159-123=36

We therefore have

3s=36

Divide both sides by 3

s=36/3

s=12

One shirt cost $12

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3 years ago
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3 years ago
A metal alloy is made by adding ½ ounce of metal C and ⅓ ounce of metal D. What is the total weight of the alloy?
Sergio [31]
5/6 Oz 
Hope This Helps!

5 0
3 years ago
Read 2 more answers
Rachel has 60 scones. She sells them to Robbie, Cameron, Louis, Tom and
Nutka1998 [239]
We can start by writing all that we know about the problem. Let us write down how many scones each boy has:
R_{o} : x
C_{a} : x+k
L_{o} : x+2k
T_{o} : x+3k
C_{h} : x+4k
Note that k is the increase, we know it's a constant. This is not a system of equations, please keep that in mind. We will use rest of the information given to build the system. We have two variables x (the number of cookies the first boy bought) and k( the increase), that means we need to have two equations to solve this problem. 
We know that total amount of scones is 60, so we can use that information to build our first equation. We sum all of the scones and we get 60. 
R_{o}+C_{a}+L_{o}+T_{o}+C_{h}=60
5x+10k=60
We know that Robbie and Cameron combined have 3/7 of <span>Louis, Tom and Charlie combined. We can use this information to build our second equation.
</span>R_o+C_a= \frac{3}{7} (L_o+T_o+C_h)
2x+k= \frac{3}{7} (x+2k+x+3k+x+4k)
2x+k= \frac{3}{7} (3x+9k)
14x+7k=9x+27k
5x=20k
x=4k
Now this piece of information alows us to solve the first equation that we made and this will solve our problem. We simply plug in x=4k into 5x+10k=60.
5(4k)+10k=60
30k=60
k=2
Now we can plug this information into the same equation 5x+10k=60 and get x.
5x+10(2)=60
5x=40
x=8
And that's it. Now we can write out how many cookies each boy has bought.
R_{o} : x=8
C_{a} : x+k=10
L_{o} : x+2k=12
T_{o} : x+3k=14
C_{h} : x+4k=16
If you add them all up you get 60.
3 0
3 years ago
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