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2 years ago

A mealworm crawled 2.1 meters in 6 minutes. At this rate, how many meters did the mealworm crawl in 1 minute

Mathematics

1 answer:

lubasha [3.4K]2 years ago

8 0

Answer:

at this rate

mealworm crawl 0.35 m in 1 minute

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Find Slope of the line passing through each pair of points

Kisachek [45]

1) 4/2 2) 1/3 3) 3/-1

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3 years ago

Ms. Zimmer pushes a trash can and it moves across the cafeteria floor

worty [1.4K]

Answer:

Step-by-step explanation:

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2 years ago

The Paralyzed Veterans of America is a philanthropic organization that relies on contributions. They send free mailing labels an

lions [1.4K]

Answer:

Confidence interval: (0.04649,0.04913)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 100,000

Number of people who donated, x = 4781

$\hat{p} = \dfrac{x}{n} = \dfrac{4781}{100000} = 0.04781
$

95% Confidence interval:

$\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

Putting the values, we get:

$0.04781
\pm 1.96(\sqrt{\dfrac{0.04781
(1-0.04781
)}{100000}})\\\\=0.04781
\pm 0.00132\\\\=(0.04649,0.04913)$

is the required 95% confidence interval for the true proportion of their entire mailing list who may donate.

3 0

3 years ago

My has 3 times more books that grant , and grant has 6 f

Klio2033 [76]

I’m not sure what happened while you were writing this, but if I’m reading it right, “My” has 18 books. If “My” has 3 times as many as 6, that also means 3 times 6, which is 18.

7 0

3 years ago

Write 0.216 as a rational number in lowest terms

lozanna [386]

Answer:

$=\frac{27}{125}$

Step-by-step explanation:

$0.216$

$\mathrm{Multiply\:and\:divide\:by\:10\:for\:every\:number\:after\:the\:decimal\:point.}$

$\mathrm{There\:are\:}3\mathrm{\:digits\:to\:the\:right\:of\:the\:decimal\:point,\:therefore\:multiply\:and\:divide\:by\:}1000$

$=\frac{0.216\cdot \:1000}{1000}$

$=\frac{216}{1000}$

$216,\:1000$

$\mathrm{The\:GCD\:of\:}a,\:b\mathrm{\:is\:the\:largest\:positive\:number\:that\:divides\:both\:}a\mathrm{\:and\:}b\mathrm{\:without\:a\:remainder}$

$2,\:3\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}$

$=2\cdot \:2\cdot \:2\cdot \:3\cdot \:3\cdot \:3$

$2,\:5\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}$

$=2\cdot \:2\cdot \:2\cdot \:5\cdot \:5\cdot \:5$

$\mathrm{The\:prime\:factors\:common\:to\:}216,\:1000\mathrm{\:are\:}$

$=2\cdot \:2\cdot \:2$

$\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2\cdot \:2=8$

$=8$

$=\frac{8\cdot \:27}{8\cdot \:125}$

$\mathrm{Cancel\:the\:common\:factor:}\:8$

$=\frac{27}{125}$

Hence, the correct answer is $=\frac{27}{125}$

6 0

2 years ago