BRAINLIESTT ASAP! PLEASE HELP ME :) thanks!
1 answer:
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Answer:
1.
a. The slope of the function is m = -32500, and it means the change in the value of V(t) for each unitary change in the value of t.
b. The V-intercept is b = 245000, and it means the value of V(t) when t = 0, that is, the inicial value of V(t).
c. The formula is:
2. t-intercept:
The t-intercept means when the function V(t) will be zero, that is, the truck has no value anymore.
3. Graph in the image attached.
4. The domain is t = [0, 7.5385] and the range is V(t) = [245000, 0].
5.
It means the price the truck will have after 8 years. It does not make sense, because the truck can't have a negative price.
6. After 3.6 years.
7. Between 3.23 years and 5.63 years.
Step-by-step explanation:
1.
The inicial value is 245,000, and each year the value decreases 32,500, so we can write the equation:
a. The slope of the function is m = -32500, and it means the change in the value of V(t) for each unitary change in the value of t.
b. The V-intercept is b = 245000, and it means the value of V(t) when t = 0, that is, the inicial value of V(t).
c. The formula is:
2.
To find the t-intercept we just need to use V(t) = 0 and then find the value of t:
The t-intercept means when the function V(t) will be zero, that is, the truck has no value anymore.
3.
The graph of the function is in the image attached.
4.
The domain is t = [0, 7.5385] and the range is V(t) = [245000, 0].
5.
It means the price the truck will have after 8 years. It does not make sense, because the truck can't have a negative price.
6.
After 3.6 years.
7.
Between 3.23 years and 5.63 years.
Answer:
62.9% in ten years
Step-by-step explanation:
This type of growth corresponds to what is called an exponential growth, since in the expression for the number of students keep including the multiplication of the same factor as the years go by, Let's start by analyzing what happens the first year:
The initial enrollment of 750 is expected to grow by 5%, therefore after one year the enrollment should be:
After one year = Year_1 = 750 + 5% increase =
where we have used the decimal form of 5% as he factor 0.05 multiplying 750 (the initial enrollment) to give the increase.
After the second year, we consider a starting value of Year_1 enrollments that will increase another 5%, which gives: Year_2 = Year_1 + Year_1 * 0.05= Year_1 (1 + 0.05).
So replacing Year_1 by its original expression (750(1+0.05)) we notice that Year_2 = 750 * (1+0.05) * (1+0.05) = 750 * (1+0.05)^2
We can go on with this same reasoning and find that each year includes a new factor (1+0.05) to the new increasing enrollment.
At the end of 10 years, the number of enrollment will be:
which we can round to 1222 students enrolled
This means and increase of:
That is approximately 62.9%