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Kisachek [45]
3 years ago
11

What is the quotient and remainder of 26 divided by4

Mathematics
2 answers:
Sphinxa [80]3 years ago
7 0

Answer:

6 with a remainder of 2

Step-by-step explanation:

Usimov [2.4K]3 years ago
4 0

Answer:

6 with a reminder of 2 :)

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What is the constant of variation if y varies inversely as x and y = 3 when x = 6? PLZ HELP ME I DONT UNDERSTAND
mojhsa [17]

Answer:

k = 18

Step-by-step explanation:

Given that y varies inversely as x then the equation relating them is

y = \frac{k}{x} ← k is the constant of variation

To find k use the condition y = 3 when x = 6, that is

3 = \frac{k}{6} ( multiply both sides by 6 )

18 = k

The constant of variation is k = 18

7 0
3 years ago
At what points is the function y= cosx/4x continuous<br><br>​
Naya [18.7K]
There is a discontinuity at 0 since you can’t divide cos x by 0. So that would be represented in interval notation at (-infinity, 0) U (0, infinity) replace infinity with the symbol
5 0
3 years ago
What is the fifth term in the sequence defined by f(n)=3(n-3)
Sholpan [36]
The answer is n= 3.

Hope this helps.
8 0
3 years ago
Read 2 more answers
Evaluate the expression, if x=12, y=8, and z=3<br> 2xy - z^3<br> _______<br> Z
lesya [120]

Answer: 55

Step-by-step explanation:

(* is a multilpication sign)

(2xy-z^3)/z

(2*12*8-3^3)/3

(192-27)/3

165/3

=55

:) -KJ

3 0
3 years ago
What is the equation of a line which includes points (-5, 5) and (2, 5)?
sveta [45]
<h2>Hello!</h2>

The answer is:

The equation of the line which includes the points (-5,5) and (2,5) is:

y=5

<h2>Why?</h2>

To find the line which includes the points (-5,5) and (2,5) we can use the following equation:

y-y_1=\frac{y_2-y_1}{x_2-x_1}*(x-x_1)

So, using the points (-5,5) and (2,5), we have:

y-5=\frac{5-5}{2-(-5)}*(x-(-5))

y-5=\frac{0}{2+5}*(x-(-5))

y-5=0*(x+5)

y-5=0

y=5

We have that the equation of the line which includes the points (-5,5) and (2,5) is:

y=5

Have a nice day!

Note: I have attached a picture for better understanding.

8 0
3 years ago
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