In this case, whose product is 8 and whose sum is 6
2,4
the answer is (n+2)(n+4)
Lets x is the 1st consecutive even integers
x +2 :the 2nd consecutive even integers
x +4: the 3rd consecutive even integers
So sum of all 3 equals -78 then
x + (x+2) + (x+4) = -78
x + x + 2 + x + 4 = -78
Simplify
3x + 6 = -78
Subtract (-6) to both sides
3x +6 -6 = -78 - 6
Simplify
3x = -84
Divided both sides by 3
3x/3 = -84/3
x = -28
x + 2 = -28 + 2 = -26
x +4 = - 28 + 4 = -24
Double check: -28 + -26 + -24 = -78
So the three consecutive even integers are: -24, -26, -28
The smallest integer would be -28
Answer:
Step-by-step explanation:
5 consecutive multiples of 5....
x , x + 5, x + 10, x + 15, x + 20
the average is 20...
(x + x + 5 x + 10 + x + 15 + x + 20) / 5 = 20
(5x + 50) / 5 = 20
5x + 50 = 20 * 5
5x + 50 = 100
5x = 100 - 50
5x = 50
x = 50/5
x = 10......smallest number
x + 5 = 10 + 5 = 15
x + 10 = 10 + 10 = 20
x + 15 = 10 + 15 = 25
x + 20 = 10 + 20 = 30 <=== largest number
The answer to this question is a equilater triangule
