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diamong [38]
4 years ago
7

It has been conjectured by the U.S. Census Bureau that "approximately 60% of foreign-born people who live in the U.S. are not na

turalized citizens." In a national random sample of 70 foreign-born people who live in the U.S., on average, how many people would you expect to get that are not naturalized citizens? Select the best answer below.a. 28 peopleb. 42 peoplec. 4.10 peopled. None of these.
Mathematics
1 answer:
nikitadnepr [17]4 years ago
7 0

Answer:

Option B) 42 people              

Step-by-step explanation:

We are given the following in the question:

Percentage of people who live in the U.S. that are not naturalized citizens = 60%

Sample size, n = 70

We have to given an estimate for people who are not naturalized citizens.

60\%\times n\\\\=\dfrac{60}{100}\times 70 \\\\=42

Thus, 42 people are not naturalized citizens.

Option B) 42 people

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48 difference is the denominating divider; meaning 48/8 = 6 is how we first find the answer before adding on the 6 to show the difference of 8 equal shares.

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