first polygon
ext. angle=180°-120°
=60°

n=360°/60°
n=6
second polygon
n=2(6)=12
ext. ang= 360°/n = 360°/12° = 30°
int. ang = 180°-30°= 150°
answer is C
A) <DAE = 180-126 = 54
b) <EBC = 90 - 48 = 42
c) <BAE = 180-48-54=78
Answer: Find the negative reciprocal of the slope of the original line and use the slope-intercept form y=mx+b to find the line perpendicular to y=1/5x−1. y=−5x−17
The answer is J'(6, -2) M'(5,1)