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lisov135 [29]
2 years ago
11

Please help me out with this

Mathematics
1 answer:
tekilochka [14]2 years ago
7 0
Yes they are similar
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Write an expression, using an exponent, that is equivalent to 8×8×8×8
zvonat [6]

Answer:

8 to the power of 4

Step-by-step explanation:

since their are four 8, (8x8x8x8) , you have to put that into an exponent

still need proof?

8x8x8x8=4096

8 to the power of 4 = 4096

so to conclude, 8 to the power of 4 is the same thing as saying 8x8x8x8, it is jsut the exponent version

5 0
2 years ago
What is the answer to :<br> 2x (4+3) -5 x [4-(9-7)]<br> ??
ZanzabumX [31]

Answer:

8×+6×-5×{2}

8×+6×-10×

14×-10×

4×

6 0
2 years ago
Read 2 more answers
Using trial and improvement, find the solution between 5 and 6 for the following equation:
STALIN [3.7K]

Answer:

2

Step-by-step explanation:

that is √ 14 which is 27 ×>44.2177

4 0
2 years ago
A survey collected data on annual credit card charges in seven different categories of expenditures: transportation, groceries,
Andru [333]

Answer:

A. Null and alternative hypothesis:

H_0: \mu_d=0\\\\H_a:\mu_d\neq 0

B. Yes. At a significance level of 0.05, there is enough evidence to support the claim that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

P-value = 0.00002

C. As the difference is calculated as (population 1 − population 2), being population 1: groceries and population 2: dinning out, and knowing there is evidence that the true mean difference is positive, we can say that the groceries annual credit card charge is higher than dinning out annual credit card charge.

The point estimate is the sample mean difference d=$840.

The 95% confidence interval for the mean difference between the population means is (490, 1190).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

Then, the null and alternative hypothesis are:

H_0: \mu_d=0\\\\H_a:\mu_d\neq 0

The significance level is 0.05.

The sample has a size n=42.

The sample mean is M=840.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=1123.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{1123}{\sqrt{42}}=173.2827

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{840-0}{173.2827}=\dfrac{840}{173.2827}=4.848

The degrees of freedom for this sample size are:

df=n-1=42-1=41

This test is a two-tailed test, with 41 degrees of freedom and t=4.848, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=2\cdot P(t>4.848)=0.00002

As the P-value (0.00002) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

At a significance level of 0.05, there is enough evidence to support the claim that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

We have to calculate a 95% confidence interval for the mean difference.

The t-value for a 95% confidence interval and 41 degrees of freedom is t=2.02.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.02 \cdot 173.283=350

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 840-350=490\\\\UL=M+t \cdot s_M = 840+350=1190

The 95% confidence interval for the mean difference is (490, 1190).

7 0
2 years ago
A set of three lines that has one point of intersection
ryzh [129]
This construction called a pencil of lines. That figure can have 3,4,5.... any number of  straights lines. The main rule is their common point. And it looks like spokes of a wheel. Here you can find a lot of vertical angles and rays.
6 0
3 years ago
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