To round the number value of 160, 656 to the nearest then
thousand, we first disband the value into its expanded form and identify the
place order of the numbers.
<span>1. 100, 000 =
hundred thousand</span>
<span>2.60, 000 =
ten thousand</span>
<span>3.600 =
hundreds</span>
<span>4.50 = tens</span>
<span>5.6 = ones</span>
Hence, the 60, 000 here is the value where the ten thousand
is, this is where we shall round off the number. Therefore the value becomes,
160,000. Take note of 0-4 rounding rules.
Solve for y
eliminate x
multiply firs tequation by -5 and 2nd by 3 and add them
-15x-30y=-15
<u>15x-3y=81 +</u>
0x-33y=66
-33y=66
divide both sides by -33
y=-2
the y coordinate is y=-2
24.4 mL
By converting mm to cm, we get
1 mm = 1/10 cm
18 mm = 18/10 cm
radius (r) = 1.8 cm
To find the volume,
Volume of sphere = 4/3πr3
= 4/3π(1.8)3
Volume = 24.4 cm3
To find the capacity,
1 cm3 = 1 mL
Capacity = 24.4 mL
<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
