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True [87]
3 years ago
6

I need help with #12

Mathematics
1 answer:
Serjik [45]3 years ago
4 0

Answer:

B

Step-by-step explanation:

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Help as soon possible thank you ​
Sergeeva-Olga [200]

<u>Answer:</u>

The correct answer option is D. (-2, 1).

<u>Step-by-step explanation:</u>

We are given the coordinates of the square A"B"C"D" after the rule is applied and we are to find the coordinates of the vertex A.

For that, we will reverse the rule.

A" = (-5, -3)

x: - 5 + 4 = -1

y: - 3 + 1 = -2

Now we will reverse the 90 degrees counter in counter clockwise rotation:

(x, y) ---> (y, -x)

(-1. -2) ---> (-2, -(-1)) = (-2, 1)

8 0
4 years ago
- What is the equation of a cirde with a center
wlad13 [49]

Answer:

<h2>C.</h2>

Step-by-step explanation:

The equationof a circle:

(x-h)^2+(y-k)^2=r^2

<em>(h, k)</em><em> - center</em>

<em>r</em><em> - radius</em>

<em />

We have <em>center = (4, -1) → h = 4, k = -1</em>, and <em>r = 9</em>.

Substitute:

(x-4)^2+(y-(-1))^2=9^2\\\\\huge\boxed{(x-4)^2+(y+1)^2=81}

6 0
3 years ago
Read 2 more answers
What do I do if I fail an online Course in HS
mario62 [17]
I really don’t know maybe you’ll have summer school that’s what we have to do if we fail an online course we have to go to summer school.
5 0
3 years ago
When she graduates college, linda will owe $43,000
Ad libitum [116K]

Answer:

Good For Her

Step-by-step explanation:

She is now in debt of 43,000 and she will now be poor

3 0
3 years ago
A page should have perimeter of 42 inches. The printing area within the page
Tamiku [17]

Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

<u>Step-by-step explanation:</u>

We have , A page should have perimeter of 42 inches. The printing area within the page  would be determined by top and bottom margins of 1 inch from each side, and the  left and right margins of 1.5 inches from each side. let's assume  width of the page be x inches  and its length be y inches So,

Perimeter = 42 inches

⇒ 2(x+y) = 42\\x+y = 21\\y = 21-x

width of printed area = x-3  & length of printed area = y-2:

area = length(width)

area = (x-3)(y-2)\\area = (x-3)(21-x-2)\\area = (x-3)(19-x)\\area = -x^{2} + 22x -57

Let's find \frac{d(area)}{dx}:

\frac{d(area)}{dx} = \frac{d(-x^{2}+22x-57)}{dx} = -2x +22 , for area to be maximum \frac{d(area)}{dx}= 0

⇒ -2x+22 = 0\\2x =22\\x=11 inches

And ,

y = 21-x\\y = 21-11\\y = 10 inches

∴ Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

7 0
3 years ago
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