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WARRIOR [948]
3 years ago
15

I GIVE YOU BRAINLIEST IF YOU HELP ME WITH THIS. Please guys I beg. I'm the dumbest person on earth.

Mathematics
2 answers:
MrRissso [65]3 years ago
8 0

Answer:

You didn't even post the question how are we supposed to help you

Step-by-step explanation:

ladessa [460]3 years ago
8 0

Answer:quit

Step-by-step explanation:what's the question?

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Who had the quickest average time per mile?
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Can you tell me what the answer is?
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2 years ago
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Shoppers at a mall have a mean weight of 70 kg 70kg70, start text, k, g, end text with a standard deviation of 10 kg 10kg10, sta
anygoal [31]

Answer:

The answer is below

Step-by-step explanation:

Shoppers at a mall have a mean weight of 70 kg with a standard deviation of 10 kg. An elevator at the mall holds a maximum of 6 people, and safety engineers are curious about the average weight of shoppers on a full elevator. Suppose that we take random samples of 6 shoppers and calculate the mean weight x ˉ  on top of the shoppers in each sample.

Solution:

Let variable x represent the weight of a shopper at the mall.

Assuming this variable has a normal distribution with mean μ= 70kg and standard deviation σ = 10kg.  

There are random samples of 6 shoppers. That is sample size (n) = 6  

The mean of the sample (μₓ) is the same as the mean of the population (μ), hence:

μₓ = μ = 70 kg

The standard deviation of the sample (σₓ) is equal to the standard deviation of the population (σ) divided by the square root of the sample size (n).. Hence:

σₓ = σ / √n = 10 / √6 = 4.08 kg

5 0
3 years ago
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