Ed has some money. He spends £7.50 on a shirt and now has one-third of what he started with.

The New England Cheese Company produces two cheese spreads by blending mild cheddar cheese with extra sharp cheddar cheese. The

Bess [88]

Answer:

They would produce 14,400 packages of zetsy and the regular profit making would be $11,340.

Step-by-step explanation:

12-ounce

regular = 65%

mild = 35%

extra sharp zesty blend = 75%

extra sharp mild = 25%

8,100 mild for = $1.30

3,500 extra sharp = $1.50

cost blend and package = $0.30

regular sold = $1.8

zesty = $2.10

first we calculate the cost of each product

conversion Of ounces to pounds:

1 pound = 16 ounces

regular cost:

12/16 pounds x 65% mild x $1.30

= 0.63375

12/16 pounds x 35% sharp x $1.50

= 0.39375‬

+ blend and package $0.30

total = $1.3275‬

contribution: $1.8 – $1.3275

= $0,4725‬

zesty cost:

12/16 pounds x 75% mild x $1.30

= 0.73125‬

12/16 pounds x 25% sharp x $1.50

= 0.28125‬

+ blend and package 0.30

total $1,3125‬

contribution: $2.10 – $1.3125

= $0,7875‬

to maximize profit:

profit = $0.4725Regular + $0.7875zetzy

adding the constraint:

mild = Regular x $0.4775 + Zetzy x $0.5625 = 8,100

and

sharp = Regular x $0.2625 + Zetzy x $0.1875 = 3,100

contribution generated by each product/pound:

Regular Zesty

CM $ 0.47250 $ 0.47250

Constrain resource

( pounds of mild) 0.48750 0.56250

CM per constrain $ 0.9692 $ 1.4000

Constrain resource

( pounds of sharp) 0.26250 0.18750

CM per constrain $ 1.80 $ 4.20

As zesty is better we produce as much as we can:

8,100 pounts / 0.5625 per cheese spreads: 14,400

check for possibilities of other constraint:

14,400 zesty packages x 0.1875 pounds each = 2,700 pounds

because it’s possible we only produce zetsy

profit = $0.4725 (0) + $0.7875 (14,400)

profit = $ 11,340

4 0

3 years ago

Evaluate S5 for 300 + 150 + 75 + … and select the correct answer below. 18.75 93.75 581.25 145.3125

Savatey [412]

we have that

$300 + 150 + 75 +...$

Let

$a1=300\\ a2=150\\ a3=75$

we know that

$\frac{a2}{a1} =\frac{150}{300} \\\\ \frac{a2}{a1}=0.5 \\ \\ a2=a1*0.50$

$\frac{a3}{a2} =\frac{75}{150} \\\\ \frac{a3}{a2}=0.5 \\ \\ a3=a2*0.50$

so

$a(n+1)=an*0.50$

Is a geometric sequence

Find the value of $a4$

$a(4)=a3*0.50$

$a(4)=75*0.50$

$a(4)=37.5$

Find the value of $a5$

$a(5)=a4*0.50$

$a(5)=37.5*0.50$

$a(5)=18.75$

Find $S5$

$S5=a1+a2+a3+a4+a5\\ S5=300+150+75+37.5+18.75\\ S5=581.25$

therefore

the answer is

$581.25$

Alternative Method

Applying the formula

$S_n=\frac{a_1 (1-r^n)}{1-r} \\\\a_1=300 \\ r=\frac{1}{2}\\\\ S_5=\frac{300(1-(\frac{1}{2})^5)}{1-\frac{1}{2}}\\\\=\frac{300(1-\frac{1}{32})}{\frac{1}{2}}\\\\=\frac{300 \times \frac{31}{32}}{\frac{1}{2}}\\\\=\frac{75 \times \frac{31}{8}}{\frac{1}{2}}\\\\=\frac{\frac{2325}{8}}{\frac{1}{2}}\\\\=\frac{2325}{8} \times 2\\\\=\frac{2325}{4}\\\\=581 \frac{1}{4}\\\\=581.25$