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gayaneshka [121]
3 years ago
7

the number of tadpoles in the pond triples each day. which graph best represents the relationship between time and the number bc

f tadpoles
Mathematics
1 answer:
OverLord2011 [107]3 years ago
5 0

Answer: it’s the b graph, like the one that curves.

Step-by-step explanation:

i just got it right on khan

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3 years ago
The revenue equation (in hundreds of millions of dollars) for barley production in a certain country is approximated by R(x) = 0
STatiana [176]

Answer:

The marginal-revenue equation is R'(x)=0.1226x+1.1584.

The marginal revenue for the production of 200,000,000 bushels is R'(x)=1.4036.

The marginal revenue for the production of 650,000,000 bushels is R'(x)=9.1274.

Step-by-step explanation:

The derivative R'(x) of the revenue function is called the marginal revenue function and is the rate of change of revenue with respect to the number of units sold.

We know the revenue function, R(x) = 0.0613x^{2} +1.1584x+2.4813. Therefore, the marginal revenue function is

R'(x)=\frac{d}{dx}R(x) = \frac{d}{dx}(0.0613x^{2} +1.1584x+2.4813)\\\\=\frac{d}{dx}\left(0.0613x^2\right)+\frac{d}{dx}\left(1.1584x\right)+\frac{d}{dx}\left(2.4813\right)\\\\R'(x)=0.1226x+1.1584

To find the marginal revenue for the production of:

200,000,000 bushels we use x = 2, since x is in units of hundreds of million of dollars.

R'(x)=0.1226\cdot \:2+1.1584\\\\R'(x)=0.2452+1.1584\\\\R'(x)=1.4036

650,000,000 bushels we use x = 65, since x is in units of hundreds of million of dollars.

R'(x)=0.1226\cdot \:65+1.1584\\\\R'(x)=7.969+1.1584\\\\R'(x)=9.1274

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Step-by-step explanation:

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