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Mariana [72]
2 years ago
15

Without multiplying, tell which product is larger and why.

Mathematics
1 answer:
Mademuasel [1]2 years ago
5 0

Answer:

because 6 is larger then 4

Step-by-step explanation:

up

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What is the value of the expression -38-16-(-23)?<br> O-31<br> O-45<br> O-54<br> O-77
ohaa [14]

Answer:

-31

Step-by-step explanation:

-38-16-(-23) \\ \\ =-38-16+23 \\ \\ =-54+23 \\ \\ =-31

3 0
11 months ago
3)<br> 6 cm<br> 5 cm<br> I<br> 7 cm<br> 5 cm<br> 6 cm
lord [1]

Answer:

29

Step-by-step explanation:

6 0
3 years ago
What are the zeros of the graphed function y = 1/3 (x + 3)(x + 5)?
Darya [45]

One factor will be zero, hence y will be zero, when x=-3.

The other factor will be zero, hence y will be zero, when x=-5.

The zeros of the function are x ∈ {-5, -3}.

_____

This solution makes use of the "zero product rule," which states a product is zero if and only if one or more factors is zero.

5 0
2 years ago
If f(x) = 4x - 20, what is f(4)?<br> O A. -4<br> оо<br> O B. -12<br> O c. 4<br> O D. 16
4vir4ik [10]

Answer:

A. - 4

Step-by-step explanation:

f(4) = 4(4) - 20 = 16 - 20 = - 4

7 0
3 years ago
Read 2 more answers
Franchise Business Review stated over 50% of all food franchises earn a profit of less than $50,000 a year. In a sample of 130 c
nydimaria [60]

Answer:

We need a sample size of 564.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

\pi = \frac{81}{130} = 0.6231

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.

We need a sample size of n

n is found when M = 0.04

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.6231*0.3769}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.6231*0.3769}

\sqrt{n} = \frac{1.96\sqrt{0.6231*0.3769}}{0.04}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.6231*0.3769}}{0.04})^{2}

n = 563.8

Rounding up

We need a sample size of 564.

4 0
3 years ago
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