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3 years ago

6

Y=3x^2+6x-7/(x+1)^2 Show that dy/dx = 20/(x+1)^3

1 answer:

fredd [130]3 years ago

3 0

Apply the quotient rule
d(uv) = v du/dx - u dv/dx
dx ----------------------
v^2

du/dx = 6x + 6
dv/dx = 2(x + 1)
v^2 = (x + 1)^4 so we have

dy dx = (x + 1)^2 .* (6x + 6) - (3x^2 + 6x - 7) * 2(x + 1) / (x + 1)^4

= (x + 1) [(6(x + 1)^2 - 2(3x^2 + 6x - 7) ] / (x + 1)^4

= (x^2 + 12x +6 - 6x^2 - 12x + 14 ) / (x + 1)^3

= 20 / (x + 1)^3 Answer

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Step-by-step explanation:

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Use a table of values with at least 5 values to graph the following function:

34kurt

The given expression :

$y=(\frac{1}{2})^x$

For coordinates:

put x = 0 then :

$\begin{gathered} y=(\frac{1}{2})^0 \\ y=1 \end{gathered}$

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Put x = (-3) and simplify :

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Substitute x = (-1) and simplify :

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inessss [21]

Answer:

<h2>17/35</h2>

Step-by-step explanation:

We need to get all the fractions with a common denominator before we can solve the problem.

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<h3>ANSWER: 17/35</h3>

I'm always happy to help :)

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