How do you Graph 3x+4y< -16 on the coordinate plane
1 answer:
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Answer:
see attached
Step-by-step explanation:
Take note of the inequality symbol. It is < (not ≤), so the "equal to" case is not included. That means the line 3x+4y=-16 is not part of the solution set. That boundary line is graphed as a dashed line.
Take note of where the variables are in relation to the inequality symbol. Both are on the "less than" side, so the shading of the graph will be where the values of x and y are less than those on the boundary line. The boundary line has a negative slope, so the values less than those on the boundary are to the left and below the line.
Plot the dashed boundary line 3x +4y = -16, or y = -3/4x -4, and shade the area below and to its left.
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Answer:
The answer is below.
Step-by-step explanation:
The options are not clear. I would solve a similar question.
A linear function is a function in the form:
y = mx + b; where y and x are variables, m is the slope and b is the y intercept.
From the options:
a) x(y - 5) = 2
xy - 5x = 2. Since the equation is not in the form of y = mx + b, hence it is not a linear function. It is a nonlinear function.
b) y - 2(x + 9) = 0
y - 2x - 18 = 0
y = 2x + 18. The equation is in the form of y = mx + b, hence it is a linear function.
c) 3y + 6(2 - x) = 5
3y + 12 - 6x = 5
3y = 6x - 7. The equation is in the form of y = mx + b, hence it is a linear function.
d) 2(y + x) = 0
2y + 2x = 0
2y = -2x. The equation is in the form of y = mx + b, hence it is a linear function.
