9514 1404 393
Answer:
see attached
Step-by-step explanation:
Take note of the inequality symbol. It is < (not ≤), so the "equal to" case is not included. That means the line 3x+4y=-16 is not part of the solution set. That boundary line is graphed as a dashed line.
Take note of where the variables are in relation to the inequality symbol. Both are on the "less than" side, so the shading of the graph will be where the values of x and y are less than those on the boundary line. The boundary line has a negative slope, so the values less than those on the boundary are to the left and below the line.
Plot the dashed boundary line 3x +4y = -16, or y = -3/4x -4, and shade the area below and to its left.
So the Rational Zeros Theorem states that <u>the potential zeros are ± P/Q, with P = factors of the constant and Q = factors of the leading coefficient.</u>
In this case, the constant is -3 and the leading coefficient is 2.
With P and Q established, divide them all as such:
<u>In short, your potential zeros are ± 1/2, ± 3/2, ± 1, and ± 2.</u>