Answer:
what? please give more details 
Step-by-step explanation:
 
        
             
        
        
        
Answer:
 P(-1 < z < 1)  = 0.3174
Step-by-step explanation:
Mean (μ) = 1.62 ounces
Standard Deviation (σ) = 0.05
No of balls (sample size n) = 100
X = weight of a ball
Weight of a group of 100 balls must lie in the range 162 ± 0.5 ounces i.e. weight of a single ball will be 162/100 ± 0.5/100 ounces = 1.62 ± 0.005 ounces.
So, we need to find the probability P (1.615 < X < 1.625). We will use the central limit theorem.
z = (Χ' - μ)/(σ/ )
)
P (1.615 < X < 1.625) = ( < (Χ - μ)/(σ/
 < (Χ - μ)/(σ/ ) <
) <  )
)
                                 = (-1 < z < 1)
We need to find the probability of P (-1 < z < 1) by looking at the Normal Distribution Probability Table. 
In order to make our working simpler, we need to break P (-1 < z < 1) into two parts: P(z < 1) and P(z > -1)
The probability for areas under the normal curve are given for P(z>X) so we can directly find the probability of P (z > -1) by referring to the normal probability table.
P(z > -1) = 0.1587
We can calculate P(z < 1) by subtracting P(z >1) from the total probability (i.e. 1). P(z >1) can be obtained from the normal probability table. 
P(z < 1) = 1 - 0.8413 = 0.1587
By adding the two probabilities together, we get:
 P(-1 < z < 1) = P(z < 1) + P (z > -1)
                    = 0.1587 + 0.1587
 P(-1 < z < 1)  = 0.3174
 
        
             
        
        
        
Answer:
C
Step-by-step explanation:
-5x-49>113
     +49  +49
———————-
-5x>162
—-   ——
-5     -5
x<32.4
 
        
             
        
        
        
Step-by-step explanation:
1<u>/</u><u>3</u><u>x</u><u>+</u><u>1</u><u>/</u><u>4</u><u>0</u><u> </u><u>=</u><u>1</u><u> </u><u>2x – 3y = –30 –8 –3 3 8</u><u> </u><u> </u>
 
        
                    
             
        
        
        
Answer:
discriminant is zero (0)
Step-by-step explanation:
Actually, you have a double root here:  {6, 6}:  "two real, equal roots."  That tells us immediately that the value of the discriminant was zero (0).