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Veronika [31]
2 years ago
15

{(-1, -1) (3.8) (2, 4)(2, 3), (7. -7) }

Mathematics
1 answer:
vodka [1.7K]2 years ago
4 0

jStep-by-step explanation:

I cannot see the question

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Since the x value can be changed to anything other than 4 (because then you would be dividing by 0 in x-4), the answer is: All real numbers except 4.
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Are there any ethical responsibilities that
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X^2+ 6x - 4 = 3x + 6
jolli1 [7]

Answer:

x=2

x=-5

Step-by-step explanation:

You need to get everything on one side to have a quadratic equation:

x^2+6x-4 -(3x+6) = x^2+3x-10

All factors of 10 are 1*10 and 2*5.

5-2 = 3 and 5*-2 = -10

Factoring x^2+3x-10 gives us (x-2)(x+5)

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3 years ago
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James is 46 years old. This is uncle John's age divided by 2, plus 14 years
Simora [160]
Uncle John is 37 hope this helps out Bc y’all helped me when I needed it
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3 years ago
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Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> In 2x - In(3x - 1) = 0
LenKa [72]

Answer:

\frac{-1}{3x^2-x}

Step-by-step explanation:

  1. If f(x) is in th form of f(x)=g(x)-h(x) then f'(x)=g'(x) - h'(x)
  2. When f(x)=z(g(x)) then f'(x)= z'(g(x))g'(x) (called as chain rule)

<u>using these information</u>:

g(x)=ln2x then g'(x)=\frac{(2x)'}{2x} =\frac{2}{2x}=\frac{1}{x}

h(x)=In(3x - 1) then h'(x)=\frac{(3x-1)'}{3x-1} =\frac{3}{3x-1}f'(x)=g'(x) - h'(x) =[tex]\frac{1}{x} - \frac{3}{3x-1} =\frac{-1}{3x^2-x}

7 0
3 years ago
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