Answer:
6.25 dont fake ur grade plz
Step-by-step explanation:
Answer:
Store A: 4
Store B: 1
Store C: 3
Store D: 2
Step-by-step explanation:
I got it right
√m/3 = 4
To remove the radical sign, square both sides.
(√m/3)² = 4²
m/3 = 16
To remove the denominator of 3, multiply both sides by 3.
3 (m/3) = 3(16)
m = 48
To check: Substitute m by its value.
√m/3 = 4
√48/3 = 4
√16 = 4
4 = 4
It's a simultaneous equation:
Steps:
1.Number the equations..
a+b=77 -1
a-b=13 -2
2. Choose what variable you want to use. In this case I would use the "b". Since the signs in front of the "b's" are different, add the two equations together
a + b = 77
+ + +
a (-b) = 13
Which gives;
2a = 90
Then solve to find a:
2a=90
a= 90/2
a=45
3.Then plug the "a" value into any of the original equations to find the "b" value. I would use equation 1 since the all the variables are positive.
a + b = 77
(45) + b = 77
b=77-45
b=32
4.Solution
a=45
b=32
Answer:
In words the answer is between t=0 and t=2.
In interval notation the answer is (0,2)
In inequality notation the answer is 0<t<2
Big note: You should make sure the function I use what you meant.
Step-by-step explanation:
I hope the function is h(t)=-16t^2+32t because that is how I'm going to interpret it.
So if we can find when the ball is on the ground or has hit the ground (this is when h=0) then we can find when it is in the air which is between those 2 numbers.
0=-16t^2+32t
0=-16t(t-2)
So at t=0 and t=2
So the ball is in the air between t=0 and t=2
Interval notation (0,2)
Inequality notation 0<t<2
