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allsm [11]
3 years ago
10

3(2x-1)=5x+3+7x I do t get this cause I’m stupid

Mathematics
2 answers:
Tcecarenko [31]3 years ago
8 0

Answer:

x=-1

Step-by-step explanation:

first you multiply 3 by whats in the parenthesis (you would get 6x-3)

then on the other side you combine like terms (add 7x plus 5x=12x)

Then you would isolate X to one side by subtracting 6x from 12x

Then you would subtract 3 from the side with 12x

By now your equation would be -6=6x

so you would divide both side by negative six to get x=-1

pishuonlain [190]3 years ago
6 0

Answer:

x=-1

Step-by-step explanation:

3(2X-1)=5x+3+7x                  Distribute the 3 into the parenthesis

6x-3=5x+3+7x                      Isolate the x on one side

-6x     -6x

-3=5x+3+7x-6x

-3        -3

-6=5x+7x-6x                         Add all the x's

-6=6x                                    Divide 6 to isolate x

(-6)/6=(6x)/6

-1=x

Now you can check if it's right by inputting -1 for x and seeing if the equations equal each other

3(2(-1)-1)=5(-1)+3+7(-1)

3(-3)=-5+3-7

-9=-9                                   They equal each other so x=-1 is correct

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6 0
2 years ago
<img src="https://tex.z-dn.net/?f=5x-%20%5Cdfrac%7B%20%5Csqrt%7B%209%20%7B%20x%20%7D%5E%7B%202%20%7D%20-6x%2B1%20%5Cphantom%7B%5
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Answer:

=5x+1          or          =5x-1

Step-by-step explanation:

One is given the following equation:

5x-\frac{\sqrt{9x^2-6x+1}}{1-3x}

The problem asks one to simplify the expression, the first step in solving this equation is to factor the equation.  Rewrite the numerator and denominator of the fraction as the product of two expressions. Remember the factoring patterns:

(a-b)^2=a^2-2ab+b^2

=5x-\frac{\sqrt{9x^2-6x+1}}{1-3x}

=5x-\frac{\sqrt{(3x-1)^2}}{-(3x-1)}

Now simplify the numerator. Remember, taking the square root of a squared value is the same as taking the absolute value of the expression,

=5x-\frac{\sqrt{(3x-1)^2}}{1-3x}

=5x-\frac{|3x-1|}{-(3x-1)}

Rewrite the expression without the absolute value sign in the numerator. Remember the general rule for removing the absolute value sign:

|a-b|\\=a -b           or           (-a-b) = b-a

=5x-\frac{|3x-1|}{-(3x-1)}

=5x-\frac{3x-1}{-(3x-1)}          or          =5x-\frac{-(3x-1)}{-(3x-1)}

Simplify both expressions, reduce by canceling out common terms in both the numerator and the denominator,

=5x-\frac{3x-1}{-(3x-1)}          or          =5x-\frac{-(3x-1)}{-(3x-1)}

=5x-(-1)          or          =5x-(1)

Simplify further by rewriting the expression without the parenthesis, remember to distribute the sign outside the parenthesis by the terms inside of the parenthesis; note that negative times negative equals positive.

=5x-(-1)          or          =5x-(1)

=5x+1          or          =5x-1

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