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Serggg [28]
3 years ago
5

Solve each given equation and show your work. Tell whether it has one solution, an infinite number of solutions, or no solutions

, and identify each equation as an identity, a contraction or neither.
A) 20-4x=12-x+8-3x
B) 5x+4x-3+24+8x
C) 5x +6+2x+6+3x-15

Confusing please help
Mathematics
2 answers:
Bingel [31]3 years ago
6 0

These are three equations and three answers.


Answers:

  • A) infinite solutions, identity
  • B) one solution, x = 27, neither contradiction nor identiy
  • C) x = no solutions, contradiction

Explanation:


Equation A: 20 - 4x = 12 - x + 8 - 3x

The objective is clearing the unknown, which is to isolate it in one side of the equation.

These are the steps and properties that you need to use:


1.  Combine like terms on right side:

20 - 4x  = 20 - 4x


2. Use addition property of equality (add 4x on each side).

20 = 20 ↔ identity


Conclusion: you have gotten a condition that is always true, no matter the value of x, which means that the equation has infinite solutions and it is an identity.


Equation B: 5x + 4x - 3  =  24 + 8x (note that I placed the equal sign as it was missing)


1.  Combine like terms on each side:

9x - 3 = 24 + 8x


2. Subtraction property and addition propertiy of equality (subtract 8x and add + 3 on both sides)

x = 27 ↔ solution (neither contradiction nor identity)


Conclusion: the solution is x = 27.


Equation C: 5x + 6 = 2x + 6 + 3x - 15 (note that I placed the equal signs as it was missing)


1. Comitne like terms on the right side:

5x + 6 = 5x - 9


2. Subtraction property of equality (subtract 5x from each side)


6 = - 9 ↔ contradiction


Conclusion: the equation does not have a solution since the final equality is always false (a condradiction or absurd).


For your information, when the variable (x) dissapears and fhe final equality is always true (for example 0 = 0, or 20 = 20), the equation is an identity.

Otrada [13]3 years ago
5 0

A) 20-4x=12-x+8-3x

Bring all x values at one side and all numerical values to the other side of the equal sign and solve. Also, do not forget to change the sign when you change the side.

-4x + x + 3x = -20 + 12 + 8

-4x + 4x = -20 + 20

0 =0 No solution

B) 5x+4x-3+24+8x

this expression can only be simplified to 17x + 21 and not solved because there is no equal sign here

C) 5x +6+2x+6+3x-15

this expression can only be simplified to 10x - 3 and not solved because there is no equal sign here

Also, neither of these is an identity or contraction.

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Answer:

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Step-by-step explanation:

The complete question is presented in the attached image to this answer.

a) Halie's allowance monthly = $9

Price of a ticket in 2008 = $2

number of tickets she could buy in a month with her allowance = (9/2) = 4.5 = 4 tickets (since there are no half tickets)

b) Halie's allowance monthly = $9

Price of a ticket in 2012 = $4

number of tickets she could buy in a month with her allowance = (9/4) = 2.25 = 2 tickets (since there are no quarter tickets)

c) In 2012, Hallie's allowance was $14.00 per month. How much did her monthly allowance increase between 2008 and 2012?

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Her monthly allowance in 2012 = $14

The increase = new allowance - old allowance = 14 - 9 = $5

In percentage terms,

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% increase = 100% × (14 - 9)/9 = 55.56%

d) How much more did a carnival ticket cost in 2012 than it did in 2008?

Price of a ticket on 2008 = $2

Price of a ticket in 2012 = $4

Increase in price = 4 - 2 = $2

% increase = 100% × (4 - 2)/2 = 100%

e) Was Hallie able to buy more carnival tickets in 2008 or in 2012 with one month's allowance?

Hallie was able to buy more tickets in 2008 than in 2012.

f) What would Hallie's allowance need to be in 2012 in order for her to be able to buy as many carnival tickets as she could in 2008?

Hallie could buy 4 tickets in 2008.

Price of a ticket in 2012 = $4.

Price of 4 tickets in 2012 = 4 × $4 = $16

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Answer:

A is the correct answer

have a great day

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