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Bad White [126]
3 years ago
14

a game consists of randomly choosing a bag (labelled 1, 2 or 3) out of a choice of 100, and then again randomly, picking a ball

(red or black) from it. Each bag has the same total of balls (10). the same player is going to play the game 200 times consecutively. how many black balls should he expect to pick
Mathematics
1 answer:
Anton [14]3 years ago
4 0

Answer:

hello your question has some missing information attached below is the missing information

answer :  112 black balls

Step-by-step explanation:

Given data:

Each bag contains ; 10 balls

Total number of ball = 100 balls

<u>first: calculate the number of Black balls to be picked from the three bags</u>

From bag 1 = 0.4 * 0.35 * 10 = 1.4 balls

From bag 2 =  0.8 * 0.45 * 10 = 3.6 balls

From bag 3 = 0.3 * 0.2 * 10 = 0.6 ball

Total black balls picked = 5.6

∴ percentage of black balls picked given that each bag contains 10

5.6 / 10 * Total balls available  =  56 balls = 56% of 100 balls

Hence If the player plays this game 200 times the number of black balls he will pick = 56% * 200 =  112 balls

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Please! Need help! Please answer 6 through 10! Brainliest! As a reward!
True [87]

Answer:

6=72 cm; 7=15 cm; 8=30 in; 9)56.5 degrees; 10)40 in

Step-by-step explanation:

6) The height of the triangle is 12 cm. The base is around 10 cm. Triangles are 1/2(b)h, so:

1/2(10)=5

5*12=60 cm

72 is closest to this.

7) Volume is l*w*h, so:

2.5*1.5=3.75

3.75*4=15 cm

8) Again, the height is 5 and the base is 12. 1/2(b)h means:

1/2(12)=6

6*5=30 in

9) All triangles have 180 degrees. So first, add the degrees you know:

33.5+90=123.5

Now, subtract that from 180:

180-123.5=56.5

10) Trapezoids can be found by multiplying the height by the smaller base, so:

6*8=40 in

Hope this helped!

4 0
2 years ago
Suppose a man offered to work for 30 days at the following salary: one cent for the first day two cents for the second day four
Ivahew [28]
It would be to little because it would only be 30 cents
8 0
3 years ago
WHAT IS 1000 /60000 IT IS HARD CAN YOU PEOPLE HELP ME PLEASE
slavikrds [6]

Answer:

0.01667

Step-by-step explanation:

8 0
3 years ago
Mathematically verify the outlier(s) in the data set using the 1.5 rule.
statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

Q_1=\dfrac{11+13}{2}

Q_1=\dfrac{24}{2}

Q_1=12

And

Q_3=\dfrac{16+16}{2}

Q_3=\dfrac{32}{2}

Q_3=16

The interquartile range is:

IQR=Q_3-Q_1

IQR=16-12

IQR=4

The data values lies outside the interval [Q_1-1.5IQR,Q_3+1.5IQR] are known as outliers.

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]

[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0
3 years ago
A room has three lightbulbs. Each one has a 30% probability of burning out within the month. Write the probability as a percenta
lesantik [10]

Answer:

97.3%

Step-by-step explanation:

Let the three bulbs be A, B and C respectively.

Let P(A) denote the probability that the first bulb will burn out

Let P(B) denote the probability that the second bulb will burn out

Let P(C) denote the probability that the third bulb will burn out

Now, we are told that Each one has a 30% probability of burning out within the month.

Thus;

P(A) = P(B) = P(C) = 30% = 0.3

Now, probability that at the end of the month at least one of the bulbs will be lit will be given as;

P(at least one bulb will be lit) = 1 - (P(A) × P(B) × P(C))

P(at least one bulb will be lit) = 1 - (0.3 × 0.3 × 0.3) = 0.973 = 97.3%

3 0
3 years ago
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