Ask question

Ask question

All categories

Bad White [126]

3 years ago

14

a game consists of randomly choosing a bag (labelled 1, 2 or 3) out of a choice of 100, and then again randomly, picking a ball

(red or black) from it. Each bag has the same total of balls (10). the same player is going to play the game 200 times consecutively. how many black balls should he expect to pick

1 answer:

Anton [14]3 years ago

4 0

Answer:

hello your question has some missing information attached below is the missing information

answer : 112 black balls

Step-by-step explanation:

Given data:

Each bag contains ; 10 balls

Total number of ball = 100 balls

<u>first: calculate the number of Black balls to be picked from the three bags</u>

From bag 1 = 0.4 * 0.35 * 10 = 1.4 balls

From bag 2 = 0.8 * 0.45 * 10 = 3.6 balls

From bag 3 = 0.3 * 0.2 * 10 = 0.6 ball

Total black balls picked = 5.6

∴ percentage of black balls picked given that each bag contains 10

5.6 / 10 * Total balls available = 56 balls = 56% of 100 balls

Hence If the player plays this game 200 times the number of black balls he will pick = 56% * 200 = 112 balls

You might be interested in

What is the equation of the line that is perpendicular to y= -3x + 1 and passes through (2,3)?

Aleonysh [2.5K]

Answer:

$\large\boxed{y=\dfrac{1}{3}x+2\dfrac{1}{3}}$

Step-by-step explanation:

$\text{Let}\ k:y=_1x+b_1\ \text{and}\ l:y=m_2x+b_2.\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\============================\\\\\text{We have}\ y=-3x+1\to m_1=-3.\\\\\text{Therefore}\ m_2=-\dfrac{1}{-3}=\dfrac{1}{3}.\\\\\text{The equation of the searched line:}\ y=\dfrac{1}{3}x+b.\\\\\text{The line passes through }(2,\ 3).$

$\text{Put the coordinates of the point to the equation.}\ x=2,\ y=3:\\\\3=\dfrac{1}{3}(2)+b\\\\3=\dfrac{2}{3}+b\qquad\text{subtract}\ \dfrac{2}{3}\ \text{from both sides}\\\\b=2\dfrac{1}{3}$

3 0

3 years ago

Read 2 more answers

Jeremy is taking a photography class, but he doesn't own a camera. The class organizers will rent him a camera for $6 per day. J

Mazyrski [523]

Solving the given inequality for d, we get...

6d + 15 < 50
6d + 15-15 < 50-15 <<-- subtract 15 from both sides
6d < 35
6d/6 < 35/6 <<--- divide both sides by 6
d < 5.83

Which means that d can be any of the values in this set: {0, 1, 2, 3, 4, 5}

The smallest d can be is 0. In this scenario, Jeremy pays the $15 registration but doesn't rent the camera at all
The largest d can be is 5. In this scenario, Jeremy rents the camera for 5 days
Any larger value of d is not allowed as it would make the total cost go over $50
Notice how I'm rounding down regardless how close 5.83 is to 6

8 0

3 years ago

Read 2 more answers

PLEASE HELP I WILL REWARD BRANLIEST AND 99 POINTS!!!!

ch4aika [34]

Answer:

Step 3, because the solution should also include all the values for x between the two given values

Step-by-step explanation:

step 1

we have

$y_1=\left|x-4\right|$

$y2=1$

step 2

The graph in the given problem

step 3

Identify the solution when $y1\leq y2$

so

$\left|x-4\right|\le1$

using a graphing tool

The solution is the interval -----> [3,5]

see the attached figure

All real numbers greater than or equal to 3 and less than or equal to 5

therefore

The first step in which the student made an error is step 3

6 0

3 years ago

Read 2 more answers

Need help with some inverse trigonometric expressions, rounded to the nearest degree.

rjkz [21]

A Google or Bing search box can be your friend, if you don't have a calculator with inverse trig functions. Most calculators that have trig functions also have the inverse functions, usually after a 2nd or "shift" key. Often, there is a mode setting for degrees or radians.

arcsin(0.33) ≈ 19°
arccos(0.47) ≈ 62°
arctan(1.21) ≈ 50°
arcsin(0.82) ≈ 55°

6 0

3 years ago

The time needed for all college students to complete a certain paper-and-pencil maze follows a normal distribution with a popula

oee [108]

Answer:

The correct option is a

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 30\ seconds$

The standard deviation is $\sigma = 3 \ seconds$

The sample size is n = 9

The null hypothesis is $H_o: \mu = 30$

The alternative hypothesis is $H_a : \mu \ne 30$

The level of significance is $\alpha = 0.01$

The sample mean is $\= x = 31.2$

Generally the test statistics is mathematically represented as

$z = \frac{ \= x - \mu }{ \frac{\sigma}{\sqrt{n} } }$

=> $z = \frac{ 31.2 - 30}{ \frac{3}{\sqrt{9} } }$

=> $z = 1.2$

From the z table the area under the normal curve to the right corresponding to 1.2 is

$P(Z > 1.2) = 0.11507$

Generally the p-value is mathematically represented as

$p-value = 2 * P(Z > 1.2)$

=> $p-value = 2 *0.11507$

=> $p-value = 0.230$

From the value obtained w can see that

$p-value > \alpha$ hence

The decision rule is

Fail to reject the null hypothesis

The conclusion is there is not enough evidence to support the claim

6 0

3 years ago