Need help with some inverse trigonometric expressions, rounded to the nearest degree.
1 answer:
A Google or Bing search box can be your friend, if you don't have a calculator with inverse trig functions. Most calculators that have trig functions also have the inverse functions, usually after a 2nd or "shift" key. Often, there is a mode setting for degrees or radians.
arcsin(0.33) ≈ 19°
arccos(0.47) ≈ 62°
arctan(1.21) ≈ 50°
arcsin(0.82) ≈ 55°
arcsin(0.33) ≈ 19°
arccos(0.47) ≈ 62°
arctan(1.21) ≈ 50°
arcsin(0.82) ≈ 55°
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A rigid transformation preserves the dimensions of the image
The option that gives the sequence of transformation that takes ΔB to ΔB is the option B.
<u>(B) Reflection across y-axis and a translation 2 units down </u>
Reason:
Question: The sequence of transformation that takes ΔA to image ΔB
<em>From a similar question, we have, ;</em>
<em>The vertices of triangle ΔA are; (-8, 9), (-9, 4), (-3, 4)</em>
<em>The vertices of triangle ΔB are; (8, 7), (3, 2), (9, 2)</em>
<em>The options are; </em>
<em>(A) Reflection over the x-axis and 2 units translation down</em>
<em>(B) Reflection over the y-axis and 2 units translation down</em>
<em>(C) 90° rotation after a translation of 2 units down</em>
<em>(D) 90° rotation after a translation of 12units right</em>
Solution;
The length of the base of ΔA = -3 - (-9) = 6
The length of the base of ΔB = 9 - 3 = 6
Therefore, the length s of triangle A and triangle B are equal
The orientation of the base of ΔA and ΔB are both horizontal
The location of the the side that traverses four cells are both furthest from the y-axis, or the vertical
Therefore, ΔB is a reflection of ΔA across the y-axis
We also have;
The base of ΔB is 2 units lower than the base ΔA
Therefore, the correct option is option B, reflection across y-axis and a translation 2 units down
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