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maria [59]
3 years ago
15

M(8, 5) is the midpoint of JK. The coordinates of point J are (5, −6) . What are the coordinates of point K? Enter your answer i

n the boxes. ( , )
Mathematics
2 answers:
kkurt [141]3 years ago
8 0

Answer:

(11,16)

Step-by-step explanation:

Hello

if you have two points , the midpoint is given by:

P1(x_{1},y_{1} )\\P2(x_{2},y_{2})\\\\Midpoint(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})\\

Step 1

Let

P1=J(5,-6)

Midpoint=M(8,5)

P2=k=?

Midpoint(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})\\so\\\\M(8,5)=(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})\\\\Hence\\8=\frac{x_{1}+x_{2}}{2}\ and\ 5=\frac{y_{1}+y_{2}}{2}\\now\ replacing\ P1\\\\\\P1=J(5,-6)\\x_{1}=5\\y_{1}=-6\\  8=\frac{5+x_{2}}{2}\ \\\ 5=\frac{-6+y_{2}}{2}\\

Step 2

solve for X(2)

8=\frac{5+x_{2}}{2}\ \\\ \\\\8*2=5+x_{2} \\16-5=x_{2} \\x_{2} =11

Step 3

solve for y(2)

5=\frac{-6+y_{2}}{2}\\5*2=-6+y_{2}\\10+6=y_{2}\\y_{2}=16

Hence the coordinates are

K(11,16)

Have a good day

Mice21 [21]3 years ago
6 0
Let the coords of K be (x,y).
The midpoint is the average of the coords of the endpoint. So 8=(5+x)/2, making x=11. And 5=(-6+y)/2 making y=16.
So K is (11,16).
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Answer:

a)Slope: \hat \beta_1 =\frac{7625.9}{1248.9}=6.106

Intercept: \hat \beta_o = 157.955 -6.106 (69.686)=-267.548

b) r=\frac{7625.9}{\sqrt{[1248.9][94228.8]}}=0.657  

And the determination coeffecient is r^2 = 0.657^2 =0.432  

Step-by-step explanation:

Data given and definitions

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"    

When we conduct a multiple regression we want to know about the relationship between several independent or predictor variables and a dependent or criterion variable.  

n=110, \sum x_i y_i = \sum (X-\bar X)(Y-\bar Y) =7625.9,\sum x^2_i=\sum (x-\bar x)^2 =1248.9 , sum y^2_i=\sum(y-\bar y)^2 =94228.8  

\sum Y_i =17375 , \sum X_i = 7665.5

Part a

The slope is given by this formula:

\hat \beta_1 =\frac{\sum (x-\bar x) (y-\bar y)}{\sum (x-\bar x )^2}

If we replace we got:

\hat \beta_1 =\frac{7625.9}{1248.9}=6.106

We can find the intercept with the following formula

\hat \beta_o = \bar y -\hat \beta_1 \bar x

We can find the average for x and y like this:

\bar X=7665.5/110 =69.686, \bar y= 17375/110=157.955

And replacing we got:

\hat \beta_o = 157.955 -6.106 (69.686)=-267.548

Part b

In order to calculate the correlation coefficient we can use this formula:  

r=\frac{\sum (x-\bar x)(y-\bar y) }{\sqrt{[\sum (x-\bar x)^2][\sum(y-\bar y)^2]}}  

For our case we have this:  

n=110, \sum x_i y_i = \sum (X-\bar X)(Y-\bar Y) =7625.9,\sum x^2_i=\sum (x-\bar x)^2 =1248.9 , sum y^2_i=\sum(y-\bar y)^2 =94228.8  

So we can find the correlation coefficient replacing like this:

r=\frac{7625.9}{\sqrt{[1248.9][94228.8]}}=0.657  

And the determination coeffecient is r^2 = 0.657^2 =0.432  

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