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mestny [16]
3 years ago
9

HJ

Mathematics
1 answer:
Olin [163]3 years ago
8 0

Answer:

19 degrees

Step-by-step explanation:

From the question given

The interior angles are x+12 and x - 3

Exterior angle is <IJK = 5x-6

Using the rule that states that the sum of interior angle of a triangle is equal to the exterior

<JHI + <HIJ = <IJK

x+12 + x-3 = 5x - 6

2x+9 = 5x -6

2x - 5x = -6-9

-3x = -15

x = -15/-3

x = 5

Get <IJK

Recall that <IJK = 5x - 6

<IJK = 5(5) - 6

<IJK = 25-6

<IJK = 19 degrees

Hence the measure of <IJK is 19 degrees

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Can someone help me please?
Roman55 [17]

Answer:

X-16 the first one

Step-by-step explanation:

The first one is equal to x-4

3 0
3 years ago
A storage tank has A circumference Of 200 meters what is the area of the base of the tank
lorasvet [3.4K]

Circumference = 2 pi r

2 pi r = 200

r = 100 / pi

Area of base = pi r r

Area of base = 100*100 / pi

Area of base = 3183.1 sq. m.

6 0
3 years ago
Find two numbers a and b such that a+b=0 and ab=36
PolarNik [594]

Answer:

b = 6i   then a = -6i

b = -6i   then a = 6i

Step-by-step explanation:

a+b=0

ab=36

a = -b

a(b) = 36

-b * b = 36

- b^2 = 36

b^2 = -36

Take the square root of each side

sqrt(b^2) = sqrt(-36)

b =± 6i

a = - (± 6i)

so b = 6i   then a = -6i

b = -6i   then a = 6i

4 0
3 years ago
The circle below has center C, and its radius is 4 feet. Find the area of the sector with central angle DCE given
garik1379 [7]

Answer:

area = \frac{8}{3}pie ft^2

Step-by-step explanation:

Area of sector is given as θ/360*πr²

Where,

θ = central angel of sector, m < DCE = 60°

r = radius = 4 feet

Area of sector = \frac{60}{360}*pie*4^2

area = \frac{1}{6}*pie*16

area = \frac{1*16}{6}*pie

area = \frac{16}{6}*pie

area = \frac{8}{3}pie ft^2

Area of the sector = 8/3π ft²

5 0
3 years ago
X
sergeinik [125]

Answer:

A. x = 58°

B. x = 10m

C. a = 44°

All approximated to nearest whole number.

Step-by-step explanation:

All triangles given are right angled triangles. Therefore, we would apply the trigonometry functions to solve for each missing side and angle.

Recall: SOHCAHTOA

a. Adjacent = 4.8cm,

Hypotenuse = 9cm

Angle to find =x°

Thus, we would apply the following formula:

Cos θ = Adjacent/Hypotenuse

Cos θ = 4.8/9 = 0.5333

θ = Cos-¹(0.5333) = 57.77

x ≈ 58° (to nearest whole number)

b. Opposite side = x

Hypothenuse = 40 m

Included angle = 14°

We would use:

Sine θ = opposite/hypothenuse

Sin (14) = x/40

Multiply both sides by 40

40*sin(14) = x

40*0.2419 = x

x = 9.676 = 10 m (to nearest whole number)

c. Opposite = 87mm

Adjacent = 91mm

θ = a°

We would use:

Tan θ = opposite/adjacent

Tan θ = 87/91

Tan θ = 0.9560

θ = tan-¹(0.9560)

θ = a = 43.71

a ≈ 44° (to nearest whole number)

7 0
3 years ago
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