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Citrus2011 [14]
3 years ago
8

Solve each expression if x=-0.25 and y= -6

Mathematics
1 answer:
Vesna [10]3 years ago
7 0

Answer:

i don't know

Step-by-step explanation:

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Three six-sided fair dice are rolled. The six sides of each die are numbered 1; 2; : : : ; 6. Let A be the event that the first
valkas [14]

Answer:

1.) [A, B, C]

2.) [A', B', C']

3.) [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

4.) A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

Step-by-step explanation:

If A is the event that the first die shows an even number, then A' is the event that first die DOES NOT show an even number.

If B is the event that the Second die shows and even number, then B' is the event that second die DOES NOT show an even number.

If C is the event that the third die shows an even number, then C' is the event that third die DOES NOT show an even number.

Hence, our possible events are A, A', B, B', C, C'.

For question 1, in the event that all three dice show and even number, the expression of the event = [A, B, C]

For question two, in the event that no die shows an even number, the expression of the event = [A', B', C']

For question 3,In the event that at least one die shows an odd number, the expression of the event = [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

For question 4,in the event that at most two dice show odd numbers, the expression of the event = [A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

6 0
3 years ago
How to solve for a and b
murzikaleks [220]
\bf \begin{cases}
3=a\cdot b^0\\
75=a\cdot b^2
\end{cases}\qquad b^0=1\implies 
\begin{cases}
3=a\cdot 1\implies 3=a\\
----------\\
75=a\cdot b^2\implies 75=3\cdot b^2\\\\
\frac{75}{3}=b^2\implies 25=b^2\\\\
\pm \sqrt{25}=b\implies \pm 5 = b
\end{cases}

recall, anything raised to the 0, zero, power, is 1, with the sole exception of 0
8 0
4 years ago
A candy store sells walnuts for $8 per pound, and pecans for $2 per pound. If the store wants to create a bag of mixed nuts that
gizmo_the_mogwai [7]
Answer: 1/3 pound pecans and 2/3 pound walnuts.

Explanation: 

x ==> weight of walnuts
y ==> weight of pecans

║ x + y = 1 
║ 8x +2y = 6

║ x = 1 - y
║ 8x + 2y = 6

8(1 - y) + 2y = 6

8 - 8y + 2y  = 6

6y = 2

y = 1/3

x = 1 - 1/3 = 2/3
7 0
3 years ago
2x+3y evaluate the expression when x=2 and y=-3
ELEN [110]

Answer:

2(2)+3(-3)=

4-9=

-5

Step-by-step explanation:

3 0
3 years ago
Please help 7th grade math
max2010maxim [7]

Answer: 3.9

Step-by-step explanation: calculator

1. 39 divided by 4 divided by 2.50

3 0
3 years ago
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