Answer:
Y' = 360ex+ 30e
Step-by-step explanation:
Y=e×6x×(6x+1) × 5
y'= d/dx (e×6x ×(6x+1)×5)
y'=d/dx(30ex ×(6x+1))
y'=d/dx(180ex^2 + 30ex)
y'=d/dx(180ex^2) + d/dx (30ex)
Calculate the derivative
y'=180e×2x +30e
y'=360ex+30e
Answer:
-2.5°F
Step-by-step explanation:
-12 - 48 = -60
-60/24 = -2.5°F
Answer:
A and B
Step-by-step explanation:
This is correct on khan academy!
1) Here, QR = QP + PR
52 = 16 + PR
PR = 52 - 16 = 36
In short, Your Answer would be Option C
2) Slope of mentioned line:
m = (5+5) / (0-4)
m = 10/-4
m = -5/2
Parallel lines have same slope so it would be -5/2 as well
In short, Your Answer would be Option B
Hope this helps!
