Ask question

Ask question

All categories

3 years ago

10

Mia's office recycled a total of 9 pounds of paper over 3 weeks. After 7 weeks, how many pounds of paper will Mia's office have

recycled?
Options:
24
21
15
18

1 answer:

tankabanditka [31]3 years ago

5 0

Answer:

21

Step-by-step explanation:

average 9 pounds per three weeks

divide 9 in 3 three weeks

3 pounds per week

7 times 3 is 21

You might be interested in

Suppose two linear equations have the same slope. Is it true that the point (3, 4) is the only point that satisfies both equatio

IrinaVladis [17]

No but it is true that the two equations are parallel.

8 0

3 years ago

If 2/3 of amount x is 60, then what is 4/5 of x

frozen [14]

I think it's 72 then?

8 0

3 years ago

Dr. Thomas just started an experiment. She will collect data for 6 days. How many hours is this?

Ber [7]

6 days* 24 hours per day= 144 hours

Final answer: 144 hours

4 0

3 years ago

Read 2 more answers

There was a plate full of brownies. Tina ate 444 of the brownies. There were 161616 brownies left.

garik1379 [7]

Subtraction

161616+444= 162,060

5 0

3 years ago

Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane

liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

Answer:

$Rate = 0.935042^\circ /cm$

Step-by-step explanation:

Given

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$T(x,y) =x\sin2y$

$r = 1m$

$v = 2m/s$

Express the given point P as a unit tangent vector:

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$u = \frac{\sqrt 3}{2}i - \frac{1}{2}j$

Next, find the gradient of P and T using: $\triangle T = \nabla T * u$

Where

$\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j$

So: the gradient becomes:

$\triangle T = \nabla T * u$

$\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]$

By vector multiplication, we have:

$\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}$

$\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)$

$\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5$

$\triangle T = 0.935042$

Hence, the rate is:

$Rate = \triangle T = 0.935042^\circ /cm$

3 0

2 years ago