Answer:
x1 =2-5i*sqrt(2)
x2 =2+5i*sqrt(2)
Step-by-step explanation:
-x^2 +4x-54=0 (quadratic equation)
a=-1, b=4, c=-54
x1=(-b+sqrt(b^2-4ac))/2a
x1=(-4+sqrt(4^2 - 4*(-1)(-54))/2*(-1)
x1=(-4+sqrt(16-216))/(-2)
x1 =(-4+sqrt(-200))/(-2)
x1 =(-4+sqrt(200i^2))/(-2) i^2=-1
x1 =(-4+sqrt(100*2*i^2))/(-2)
x1 =(-4+10i*sqrt(2))/(-2)
x1 =2-5i*sqrt(2)
x2 =(-b-sqrt(b^2-4ac))/2a
x2 =(-4-10i*sqrt(2))/(-2)
x2 =2+5i*sqrt(2)
Answer:
-43 < -35
(Negative 43 is less than negative 35).
Based on PEMDAS, in this expression, we need to do multiplication first, which is 2 times 3, which is 6. Now, the expression is 14-6+42. 14-6 is 8, and 8+42 is 50, so the answer is 50.
Hope this helps!
If I'm interpreting this right, it's -36 since a half times ten is 5... so it comes down to 5-41 which equals -36.
The graph is shown in the attached image.
