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Svetach [21]
3 years ago
15

Work out 6 x (11- 3)

Mathematics
1 answer:
vitfil [10]3 years ago
8 0

Answer:

first you do 11-3 to get 8. then you multiply 8 and 6 to get 48

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Thelma spent 1/6 of her weekly allowance on dog toys.  1/4 on a dog collar and 1/3 on dog food.  What fraction of her weekly all
Paladinen [302]
To figure out you would first find a common factor with would be 12. After that 1/4 would be 3/12, 1/3 would be 4/12 and 1/6 would be 2/12. Next you just add all the numbers and get 9/12 then the remainder is you answer which comes to be 3/12 or 1/4. Hope that helps:)
3 0
3 years ago
Read 2 more answers
Help me plz!!!!! I have no ideia how to do this
BlackZzzverrR [31]

Answer:

<h2>x² = -3</h2>

Step-by-step explanation:

In algebra, the goal is always to isolate the variable, so its value can be determined.

<h3>Step 1: Subtract 21</h3>

7x² = -21

<h3>Step 2: Divide by 7</h3>

x² = -3

<h3>Step 3: Check</h3>

7(-3) + 21 = 0

0 = 0 ✔

<h3>Step 4: Answer</h3>

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I'm always happy to help :)

4 0
3 years ago
What is the estimated sum?
lyudmila [28]

Answer:

B

Step-by-step explanation:

521,370 would round to 521,400

26,839 would round to 27,800

and adding them would be

548,200

7 0
3 years ago
The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasin
hoa [83]

Answer:

\frac{dI}{dt}=-0.00016 A/s

Step-by-step explanation:

We are given that

By ohm's law

V=IR

R=389 ohm

I=0.03 A

\frac{dV}{dt}=-0.06V/s

\frac{dR}{dt}=0.07ohm/s

We have to find rate of change of current I means \frac{dI}{dt}

Differentiate the equation w.r.t t

\frac{dV}{dt}=\frac{dI}{dt}R+I\frac{dR}{dt}

Substitute the values then we get

-0.06=\frac{dI}{dt}\times 389+0.03\times 0.07

-0.06=389\frac{dI}{dt}+0.0021

-0.06-0.0021=389\frac{dI}{dt}

-0.0621=389\frac{dI}{dt}

\frac{dI}{dt}=\frac{-0.0621}{389}=-0.000160 A/s

Hence, the current I is changing at the rate=-0.00016A/s

4 0
3 years ago
ASAP PLZ IM TIMED I WILL GIVE BRAINLIEST ​
katrin [286]

Step-by-step explanation:

{ \huge{ \red{ \bf( \frac{3}{4} ) {}^{3} }}}

{ \huge{ \blue{ \bf{( \frac{3 \times 3 \times 3}{4 \times 4 \times 4} )}}}}

{ \large{ \pink{ \boxed{ \tt{ \bigg( \frac{27}{64} { \bigg)}}}ans.}}}

3 0
3 years ago
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