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arsen [322]
2 years ago
14

Which model represents the factors of x2 + 9x + 8?

Mathematics
2 answers:
Valentin [98]2 years ago
9 0

Answer:

C

Step-by-step explanation:

I got it on the test and it worked

Tomtit [17]2 years ago
5 0

Answer: the answer is D

Step-by-step explanation:

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30) On the 7th it will be 1/120
33) C
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Dawn draws 1 card, replaces it, and draws another card. Is it more likely that she draws 2 red cards or 2 face cards? Can someon
Llana [10]
Red card because it is a fifty fifty chance for the colors but a 3 in 10 chance for a face card
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baherus [9]

both the x and y line

7 0
3 years ago
Investigate the difference between compounding annually and simple interest
Gennadij [26K]

Step-by-step explanation:

Simple interest formula

A = P (1 + rt)

Compound interest formula

A = P(1 + \frac{r}{n})^{nt}

a.

A = 5000 (1 + 0.025*1)\\A=5000(1.025)\\A=5125

Simple interest is $125

b

. A = 5000 (1 + \frac{0.025}{1})^{1*1}      \\A=5000(1.025)\\A= 5125

Compound interest is $125

c. the result for both a and b are the same

d.

A = 5000 (1 + 0.025*3) \\A=5000(1.075) \\A=5375

the simple interest is $375

e

. A = 5000 (1 + \frac{0.025}{1})^{1*3}] \\A=5000(1.025)^3 \\A=5000(1.077)\\A= 5385

the compound interest is $385

f. the result compared, compound interest is $10 more than simple interest

g.

A = 5000 (1 + 0.02*6) \\A=5000(1.12) \\A=5600

the simple interest is $600

h.

A = 5000 (1 + \frac{0.02}{1})^{1*6}] \\A=5000(1.12)^6 \\A=5000(1.9738) \\A= 9869

the compound interest is $4869

i. the result from g and h, h is over 8 times bigger than g.

j. interest compound annually is not the same as simple interest, only for the case of a and b seeing that it is for 1 year. but for 2years and above there is difference as seen in c to h

6 0
3 years ago
Please help me hurry please
aalyn [17]

Answer:

y = root under 24 (evaluate it if necessary)

or y = 2 root 6

Step-by-step explanation:

Let the reference angle be x

for the triangle in left,

b = 6-4 = 2

Now,

taking x as refrence angle,

cosx = b/h

or, cosx = 2/h

again,

for the bigger triangle,

taking x as reference angle,

cosx = b/h

or, cosx = b/6

As we can see base of bigger triangle is equal to hypotenuse of triangle at the left,

Let's suppose its a

so, cosx = a/6 = 2/a

now,

a/6 = 2/a

or, a² = 12

now,

for bigger triangle, using pythagoras theorem,

h² = p²+b²

or, 6² = y² + a²

or, 36 = y² + 12

or, y² = 24

so, y = root under 24

5 0
2 years ago
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