Sq.root of 1240 is approx 35 mm
Answer:
The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>
Step-by-step explanation:
Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.
We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

Since, given the difference of the squares of the numbers is 5 that is 
And the product of the numbers is 6 that is 
Using identity, we have,

Substitute, we have,

Simplify, we have,


Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169
<h2>
Answer:</h2><h2>3:5</h2><h2 /><h2>Hope this helps!!</h2>
So probability is (disred outcomes) divided by (total possible outomces
so
hearts and clubs are 2 out of 4 total suits and since there are the same number of cards per suit, it simplifies
2=desrired oucomes
4=total possible
2/4=1/2=0.5=50%
answer is 1/2 or 0.5 or 50%