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IceJOKER [234]
3 years ago
5

Pls help ASAP I DONT have time

Mathematics
1 answer:
Valentin [98]3 years ago
4 0

Answer:

answer is b

Step-by-step explanation:

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The options are<br> 40<br> 80<br> 120<br> 140
Nataly [62]
<h2>Here we go ~ </h2>

According to given figure,

\qquad \sf  \dashrightarrow \: \angle ABC + 60° = 180°

\qquad \sf  \dashrightarrow \: \angle ABC = 180 \degree - 60 \degree

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\qquad \sf  \dashrightarrow \: \angle ABC = 120 \degree

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3 years ago
Triangle RST has vertices located at R (2, 3), S (4, 4), and T (5, 0).
LiRa [457]

The length of the sides are 2.24, 4.24 and 4.12 units while the slope are 0.5, -1 and -4.

<h3>Linear equation</h3>

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial value of y.

For RS:

  • Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(4-3)^2+(4-2)^2}=2.24   \\&#10;\\&#10;slope=\frac{y_2-y_1}{x_2-x_1} =\frac{4-3}{4-2}=0.5

For RT:

  • Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(0-3)^2+(5-2)^2}=4.24   \\&#10;\\&#10;slope=\frac{y_2-y_1}{x_2-x_1} =\frac{0-3}{5-2}=-1

For ST:

  • Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(0-4)^2+(5-4)^2}=4.12   \\&#10;\\&#10;slope=\frac{y_2-y_1}{x_2-x_1} =\frac{0-4}{5-4}=-4

The length of the sides are 2.24, 4.24 and 4.12 units while the slope are 0.5, -1 and -4.

Find out more on linear equation at: brainly.com/question/14323743

5 0
2 years ago
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