Answer:
y= -5/2 x + 14 (point slope form)
2y+5x=28 (standard form)
Step-by-step explanation:
Perpendicular lines met the following condition
m1*m2=-1 (the product of their slopes is -1)
To obtain m2, the slope of our desired line lets first re arrange the equation of the first line. 2x-5y=2, so. 2x-2=5y.
Isolating y, leads the following, result: y= 2/5 x - 2/5
m1=2/5
m2 is =-5/2
The equation of our desired line is the following
y=mx+b, we have m, which is -5/2, but still need to find value for b.
Lets now evaluate the above equation in the given point (-6,1).
1=-6 * -5/2 + b.
b=14.
Now we can say the equation that our desired line is
y= -5/2 x + 14 (point slope form)
Or... If we group variables 'x' and 'y' together
y+5/2 x = 14, we want integer coefficients, so lets multiply this expression by 2, to obtain the following:
2y+5x=28
