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Sedbober [7]
3 years ago
14

Determine the slope-intercept equation of a line with a slope of 3/2 that passes through (2, -1).

Mathematics
1 answer:
Anna35 [415]3 years ago
7 0

Answer:

\orange{ \bold{y = \frac{3}{2}x -4 }}

Step-by-step explanation:

Slope of line (m) = \frac{3}{2}

Line passes through the points (2,\:-1)=(x_1, \:y_1)

Equation of line in point slope form is given as:

y-y_1 =m(x-x_1)

Plug the values of m, x_1\: \&\: y_1 in the above equation, we find:

y - ( - 1) =  \frac{3}{2} (x - 2) \\  \\ y + 1 =  \frac{3}{2}x -  \frac{3}{2} \times 2 \\  \\ y + 1 = \frac{3}{2}x -3 \\  \\ y = \frac{3}{2}x -3 - 1 \\  \\  \purple{ \bold{y = \frac{3}{2}x -4 }}\\  \\

This is the required equation of line in <u>slope-intercept</u> form.

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_____

<em>Comment on the question and answer</em>

Your description "on the circle between points Q and N" is ambiguous. You used the same description for both points P and R. The interpretation we used is shown in the attachment. If point P is on the long arc NQ, then the measure of arc QPN will be the difference between 148° and 360°, hence 212°. You need to choose the answer that matches the diagram you have.

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We call angle QNT an "inscribed angle" because it is a degenerate case of an inscribed angle. The usual case has the vertex of the angle separate from the ends of the arc it intercepts. In the case of a tangent meeting a chord, the vertex is coincident with one of the ends of the intercepted arc. The relation between angle measure and arc measure remains the same: 1 : 2.

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