Let us call p the probability of occurence of the event D: "a student owns a dog"
and q the probability of occurence of the event C: "a student owns a cat"
In this exercice we have to assume that the events D and C are independent which means that none of them influence the occurence of the other. Because if they are not independent there really is noway to deduce q here.
In reality those events would probably not be independent since if I had a dog, I would really think twice before buying a cat ;)
Well if they are independent then you know that The Probability of occurence of D and C at the same time equals P(D)*P(C)=p*q
So we can deduce that 2/15=1/3*q
q=3*2/15
q=6/15
q=2/5
Once again this is theoritical <span />
Answer:
8x^3-7x^2-11x+9
Step-by-step explanation:
(8x^3-5x-1)-(7x^2+6x-10)
remove unnesasary ( )
8x^3-5x-1 -(7x^2+6x-10)
the distribute
8x^3-5x-1 -7x^2-6x+10
combine like terms
8x^3-11x+9-7x^2
use the communative property to reorder the equation
8x^3-7x^2-11x+9
Answer: The percentage of the people had no qualifications = 16.06%
The percentage are not breast-fed = 34.68%
Step-by-step explanation:
Given: Total people surveyed = 1800
Number of people who had no qualification = 289
The percentage of the people had no qualifications =
Total babies = 124
Number of babies breast- fed = 81
The percentage are not breast-fed =
1) Write exponent as improper fraction
1.5=3/2
2)
I am sure it B hope I helped