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3 years ago

What is a decimal equivalent of the fraction 32/45

Mathematics

2 answers:

saul85 [17]3 years ago

8 0

Answer:

0.71. with the bar notation over the 1

Step-by-step explanation:

ser-zykov [4K]3 years ago

7 0

Answer:

decimal is 0.7111 Percentage is 71.11%

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I need help with this question pls

Andrej [43]

Answer:61.8°

Step-by-step explanation:

Length of arc=(theta)/360 x 2 x π x radius

9.7=(theta)/360 x 2 x 3.14 x 9

9.7=56.52(theta)/360

cross multiply

9.7 x 360=56.52(theta)

3492=56.52(theta)

Divide both sides by 56.52

3492/56.52=56.52(theta)/56.52

61.8=theta

theta=61.8°

7 0

3 years ago

Will give <br> BRAINLY AND FIVE STARS and A THANKS

11Alexandr11 [23.1K]

Answer:

k = 12h

Step-by-step explanation:

Since each of the inputs of h can be mutiplied by 12 to get the output k, the equation is k = 12h
Hope this helps :)

3 0

2 years ago

Double the difference of a number and seven

KengaRu [80]

Answer:

2x-14

Step-by-step explanation:

2(x-7)

distribute

2x-14

4 0

2 years ago

Pls help ;/ not hard btw

Colt1911 [192]

Answer:

$- 10z - 2$

Step-by-step explanation:

this is simplify

7 0

3 years ago

The numbers of regular season wins for 10 football teams in a given season are given below. Determine the range, mean, variance,

tensa zangetsu [6.8K]

We have the following data set:

2,7,15,3,12,9,15,8,3,10

The range is the difference between the highest and lowest values in the set, to find the range, order the data set from least to greatest.

2,3,3,7,8,9,10,12,15,15

Then,

$\begin{gathered} \text{Range}=15-2 \\ \text{Range}=13 \end{gathered}$

Mean is represented by the following expression:

$\text{Mean}=\frac{\text{Sum of all data points}}{Number\text{ of data po}ints}$ $\text{Mean}=\frac{84}{10}=8.4$

Population variance formula looks like this:

$\begin{gathered} \sigma^2=\frac{\sum^{}_{}(x-\mu)^2}{N} \\ \text{where,} \\ \sigma^2=\text{population variance} \\ \sum ^{}_{}=addition\text{ of} \\ x=\text{each value} \\ \mu=population\text{ mean} \\ N=\text{ number of values in the population} \end{gathered}$

Then, substituting:

$\begin{gathered} \sigma^2=\frac{(2-14)^2+(3-14)^2+\cdots+(15-14)^2}{10} \\ \sigma^2=20.44 \end{gathered}$

For the standard deviation:

$\begin{gathered} s=\sqrt[]{\frac{\sum ^{}_{}(x-\mu)^2}{N}} \\ s=4.521 \end{gathered}$

5 0

1 year ago