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3 years ago

8

I really need help on this problem. I'm unable to answer it in standard and point slope form. Thanks. Very easy response and ans

wer gets 15 points or more

2 answers:

anyanavicka [17]3 years ago

8 0

Point Slope Formula: y-y₁=m(x-x₁)
Linear Standard Form: Ax+By=C
Slope Intercept: y=mx+b

Kobotan [32]3 years ago

6 0

Linear standard form is y=mx+b.

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Please help me if u can

Gre4nikov [31]

Answer:

What are you trying to figure out? Where the card goes?

Step-by-step explanation:

8 0

2 years ago

sergejj [24]

Answer:

8*1/4= 2

A) 0.071

B) 0.48

5 0

3 years ago

In a test of the effectiveness of garlic for lowering cholesterol, 8181 subjects were treated with raw garlic. Cholesterol leve

xz_007 [3.2K]

Answer:

With garlic treatment, the mean change in LDL cholesterol is not greater than 0.

Step-by-step explanation:

The dependent <em>t</em>-test (also known as the paired <em>t</em>-test or paired samples <em>t</em>-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

In this case a paired <em>t</em>-test is used to determine the effectiveness of garlic for lowering cholesterol.

A random sample of 81 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment.

The hypothesis for the test can be defined as follows:

<em>H₀</em>: With garlic treatment, the mean change in LDL cholesterol is not greater than 0, i.e. <em>d</em> ≤ 0.

<em>Hₐ</em>: With garlic treatment, the mean change in LDL cholesterol is greater than 0, i.e. <em>d</em> > 0.

The information provided is:

$\bar d=0.40\\SD_{d}=16.2\\\alpha =0.01$

Compute the test statistic value as follows:

$t=\frac{\bar d}{SD_{d}/\sqrt{n}}\\\\=\frac{0.40}{16.2/\sqrt{81}}\\\\=0.22$

The test statistic value is 0.22.

Decision rule:

If the <em>p</em>-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the <em>p</em>-value of the test as follows:

$p-value=P(t_{n-1}>0.22)\\=P(t_{80}>0.22)\\=0.4132$

*Use a <em>t</em>-table.

The <em>p</em>-value of the test is 0.4132.

<em>p-</em>value= 0.4132 > <em>α</em> = 0.01

The null hypothesis was failed to be rejected.

Thus, it can be concluded that with garlic treatment, the mean change in LDL cholesterol is not greater than 0.

3 0

3 years ago

As Sales Manager for ISeeYou Productions, you are planning to review the prices you charge clients for television advertisement

aksik [14]

The development fee p can be modeled by the equation p=-400q+9600 where p is the price the company charges and q is the number of contracts they get. The total revenue R ISeeYou obtains by signing q contracts is found by using the function: $R(q)=-400q^{2}+9600q$ . The cost ISeeYou Productions can be found by using the following function: C(q)=800q+16000. The monthlhy profit of Express ISeeYou Productions if found with the next function: $P(q)=-400p^{2}+8800q-16000$ . ISeeYou should sign 2 or 20 contracts to break even.

a) In order to solve part a of the problem, we will suppose the price will have a linear relation with the amount of contracts they signed, so we need to find two points to build this function.

We know that when signing 6 contracts, the company charges $7,200, so our first point will be:

(6, 7200)

we also know that the company signs 14 contracts when they charge $4,000. So our second point is:

(14, 4000)

so we can use these points to find the slope of the line by using the

slope formula:

$m=\frac{p_{2}-p_{1}}{q_{2}-q_{1}}$

$m=\frac{4000-7200}{14-6}$

so the slope is:

m=-400

We can now use one of those points and the slope to find the function for the price, so we get:

$y-y_{1}=m(x-x_{1})$

$p-p_{1}=m(q-q_{1})$

if we used the point: (6, 7200) we get:

$p-7200=-400(q-6)$

which can now be simplified:

p=-400q+2400+7200

so the price function is:

p=-400q+9600

b) In order to find the revenue equation we need to multiply the price equation by the amount of contracts they signed in a month, so we get:

R(q)=pq

$R(q)=(-400q+9600)q$

$R(q)=-400q^{2}+9600q$

c) The cost can be found by adding the fixed cost and the variable cost, so we get:

C(q)=800q+16000

d) The profit is found by subtracting the montly cost from the monthly revenue, so we get:

P(q)=R(q)-C(q)

so

$P(q)=-400q^{2}+9600q-(800q+16000)$

so we can now simplify our function to get:

$P(q)=-400q^{2}+9600q-800q-16000$

$P(q)=-400q^{2}+8800q-16000$

e) In order to find the number of contracts for the company to break even, we need to find the q contracts that will give a profit of $0 so we set the function of the previous part of the problem equal to zero so we get:

$P(q)=-400q^{2}+8800q-16000$

$-400q^{2}+8800q-16000=0$

we can start by factoring a -400 from the left side so we get:

$-400(q^{2}-22q+40)=0$

we can divide both sides of the equation into -400 to simplify the equation so we get:

$q^{2}-22q+40=0$

and now we can factor the left side of the equation to get:

(q-20)(q-2)=0

we can now split this into two equations to get:

q-2=0 and q-20=0

so our two answers are:

q=2 and q=20

the company will break even when signing 2 and 20 contracts.

In the attached picture you will be able to see the break even points on the graph of revenue and cost.

For more information on how to solve this type of problems, you can go to the next link.

brainly.com/question/23407629?referrer=searchResults

6 0

2 years ago

((x-h)^2)+((y-k)^2)

Schach [20]

Answer:

Step-by-step explanation:

= (x^2 + h^2 - 2xh) + (y^2 + k^2 - 2yk) As, (a-b)^2 = a^2 + b^2 - 2ab

= x^2 + h^2 - 2xh + y^2 + k^2 - 2yk

5 0

3 years ago