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Rama09 [41]
3 years ago
6

Which answer choice below best represents the equation for the graph above?

Mathematics
1 answer:
Fed [463]3 years ago
8 0
The answer is d : 1/2x + 2
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The lengths of trout in a lake are normally distributed with a mean of 30 inches and a standard deviation of 4.5 inches. Enter t
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The answer is -0.4....
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4 years ago
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PLEASE HELP ME. :( :(
STatiana [176]
Y = mx + b

4 = m(248) + b
6 = m(372) + b
subtract the two equations to get
-2 = m(-124) + 0
m = 1/62

Then plug in m into one of the equations to find b
4 = (1/62)(248) + b
4 = 4 + b
b = 0

So the equation is
y = (1/62)x + 0
or
y = (1/62)x
or
y = x/62

edit: I totally didn't use point slope. It should be
        y + 0 = (1/62)(x + 0)
        or  y = (1/62)x

(since b is 0, that means she started driving directly at home)
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2) 150mi/1.25hr = Xmi/5hr
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Question in photo, Please Help
quester [9]
The answer would be 28 feet, to get area you do length times width, 7 x 4 = 28
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Given that ∠A≅∠B , Gavin conjectured that ∠A and ∠B are complementary angles.
Pani-rosa [81]

Given ∠A≅∠B which means A and B are congruent, so A and B should have same value.

and also given that A and B are complementary angles which mean ∠A+∠B=90°

Now to find counterexample to Gavin's statement, we should find two angles satisfying ∠A≅∠B and contradicting ∠A+∠B = 90°

Let us check given options:-

A) since A and B are not equal, it is contradicting the first statement itself.

B) Here ∠A=25 = ∠B , hence it is satisfying congruent condition.

Let us check they are complementary or not by adding them.

∠A+∠B = 25°+25° = 50° ≠90°

Which means it is an counter example to Gavin's statement which tells that two congruent angles need not be complementary.

C) since A and B are not equal, it is contradicting the first statement itself.

D) Here ∠A=45°=∠B, hence it is satisfying congruent condition.

And ∠A+∠B = 45°+45° = 90°

Hence this is not an counter example.

4 0
3 years ago
12overx+7=13over X what's the answer
photoshop1234 [79]
12/x + 7 =13/x, where x is not 0;
<=> 12 + 7x = 13 <=> 7x = 1 <=> x = 1/7;
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