Answer:
Increases
Step-by-step explanation:
It increases because, the greater the value of x the smaller the fraction is. If x was 25 the fraction would be 5/25 this makes the value of the equation 5.2. Now if x was a smaller positive number like 5. Then the fraction would be 5/5 which would cause the equation to be equal to 6.
Answer:
3 cakes
You need to add 4.5 until you get the closest you can get to 16 with out going over.
<h3>
Answer: 9 units</h3>
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Explanation:
Let's calculate the volume of one small spherical bead
V = (4/3)*pi*r^3
V = (4/3)*pi*3^3
V = 36pi
The volume of 27 such identical beads is 27*36pi = 972pi cubic units.
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This is the new volume and we'll use this to find the radius r of the larger sphere.
V = (4/3)*pi*r^3
972pi = (4/3)*pi*r^3
3*972pi = 4pi*r^3
2916pi = 4pi*r^3
r^3 = (2916pi)/(4pi)
r^3 = 729
r = (729)^(1/3)
r = 9 units is the radius of the larger gold sphere
Answer:
10
Step-by-step explanation
The earthquake measures 6.4 on the Richter scale which struck Japan in Jullu 2007 and caused and extensive damage. Earlier that year, a minor earthquake measuring 3.1 in the Richter scale has stroked in parts of Pennsylvania.
Fomular:
The magnitude of an earthquake is M log(I/S)
where I donates the intensity of the earthquake and S be the intensity of the standard earthquake.
Calculation:
Consider that M1 be the magnitude Japanese earthquake and M2 be the magnitude of the Pennsylvania earthquake and L1 be the intensity of the Japanese earthquake and L2 the intensity of the Pennsylvania earthquake.
Here the magnitude of the Japanese earthquake is M1 = 6.14 and the magnitude of the Pennsylvania is M2 = 3.1
By the use of magnitude of the earthquake fomular M = log I1/S, the intensity of the Japanese earthquake is calculated as follows .
M1 = log I1/S
I1/s = 10
