A line parallel to the given one will have the same slope, 0.5. For the purpose here, it is convenient to start with a point-slope form of the equation, then simplify. For slope m and point (h, k), the equation of the line can be written as
... y = m(x -h) +k
We have m=0.5, (h, k) = (-9, 12), so the equation is ...
... y = 0.5(x +9) +12
... y = 0.5x +16.5
I’m not sure how your class works, but usually if they are circled it means you only have to do the circled ones. GCF always stands for greatest common factor
A rectangle is plotted on the coordinate grid. It has vertices at (-3, 5), (4, 5), (4, -1), and (-3, -1). Which choices below are the dimensions of the rectangle?
Answer
(-3,5)
Answer:
- b/a
- 16a²b²
- n¹⁰/(16m⁶)
- y⁸/x¹⁰
- m⁷n³n/m
Step-by-step explanation:
These problems make use of three rules of exponents:

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)
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1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

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2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

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3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

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4. This works the same way the previous problem does.

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5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

It is A, 60° because 180° (degree of the whole triangle) divided by the three angles is 60.