It’s A…..HL postulate
Adiós XD
When two parallel lines are intersected by a transversal, the same-side exterior angles are supplementary. That means that their sum is 180.
Using that logic, if the two roads were parallel, then the sum of their same-side exterior angles will add up to 180. Yet their same-side exterior angles add up to 170 (130 + 40 = 170), hence they can't be parallel.
See the drawing attached below.
Using supplmenatry angles (two angles whose sum of measures add up to 180 or a straight line), we can say that:
m<DIE + m<HID = 18
40 + m<HID = 180
m<HID = 140
Similarly:
m<BHC + m<CHI = 180
130 + m<CHI = 180
m<CHI = 50
Using verticle angles therome, (when two lines intersect, the angles opposite to eachother are congruent, or have the same measure), we can say that:
m<DIE = m<GIH = 40
m<GIE = m<HID = 140
m<CHI = m<AHB = 50
m<BHC = m<AHI = 130
Answer: x = 9, 5
<u>Step-by-step explanation:</u>
4 | x - 7 | + 2 | x - 7 | = 12
6 | x - 7 | = 12 <em>added like terms</em>
| x - 7 | = 2 <em>divided both sides by 6</em>
x - 7 = 2 or x - 7 = -2 <em>removed absolute value sign</em>
x = 9 or x = 5 <em>added 7 to both sides of both equations</em>
A. (4+16)/2 = (4+10+16)/3 =10
Answer:
Estimate: 7
Actual: 6.63 (>)
Step-by-step explanation:
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