PART A
s = <span>the number of packets of strawberry wafers ;
c = </span><span>the number of packets of chocolate wafers ;
3 </span>× s + 1 × <span>c = 30 ;
s + c = 22 ;
PART B
</span>The method of solving "by substitution"<span> works by solving one of the equations (you choose which one) for one of the variables (you choose which one), and then plugging this back into the other equation, "substituting" for the chosen variable and solving for the other. Then you back-solve for the first variable.
</span>
c = 30 - 3s;
s + ( 30 - 3s ) = 22;
30 - 2s = 22;
30 - 22 = 2s;
8 = 2s;
s = 4 ;
c = 30 - 12 ;
c = 18 ;
Answer:
No solutions
Step-by-step explanation:
|-2x-10| + 4 = 2
Subtract 4 from each side
|-2x-10| + 4-4 = 2-4
|-2x-10| = -2
The absolute value is negative so there are no solutions.
Absolute values are always positive, so they cannot be negative.
Answer:
5/4 as a mixed number = 1
Given:
Consider the given expression is

To find:
The simplified form of the given expression.
Solution:
We have,

Using properties of exponents, we get
![[\because a^ma^n=a^{m+n}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5Ema%5En%3Da%5E%7Bm%2Bn%7D%5D)




Therefore, the simplified form of given expression is 25.