Answer:
2
Step-by-step explanation:
1. go to desmos Graphing calculator and select graphing calculator
2. Next type in the word length then it should look like this Length
3. Don't space just put this ( and type in the point it should look like this Length(-2,-3),(4,4)
4. Be sure to do double () it should look like this Length((-2,-3),(4,4))
5. It should give you your answer
Answer:
P(3) is true since 2(3) - 1 = 5 < 3! = 6.
Step-by-step explanation:
Let P(n) be the proposition that 2n-1 ≤ n!. for n ≥ 3
Basis: P(3) is true since 2(3) - 1 = 5 < 3! = 6.
Inductive Step: Assume P(k) holds, i.e., 2k - 1 ≤ k! for an arbitrary integer k ≥ 3. To show that P(k + 1) holds:
2(k+1) - 1 = 2k + 2 - 1
≤ 2 + k! (by the inductive hypothesis)
= (k + 1)! Therefore,2n-1 ≤ n! holds, for every integer n ≥ 3.
