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inessss [21]
2 years ago
9

AJLK ~ APQR. Find the value of . 22 14 7 1 8 K 16 20 2=

Mathematics
1 answer:
In-s [12.5K]2 years ago
5 0

Answer:

x = 11

Step-by-step explanation:

sides are proportional so you can set up a proportional and cross-multiply:

JL is to PQ as LK is to QR

x/22 = 8/16

x/22 = 1/2

2x = 22

x = 11

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Please help me find the area of shaded region and step by step​
Bumek [7]

Answer:

Part 1) A=60\ ft^2

Part 2) A=80\ cm^2

Part 3) A=96\ m^2

Part 4) A=144\ cm^2

Part 5) A=9\ m^2

Part 6) A=(49\pi -33)\ in^2

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

A=bh

where

b is the base of rectangle

h is the height of rectangle

so

A=(12)(7)-(8)(3)

A=84-24

A=60\ ft^2

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

A=b^2

where

b is the length side of the square

so

A=(12)(8)-(4^2)

A=96-16

A=80\ cm^2

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

so

A=4(4)(5)+(4^2)

A=80+16

A=96\ m^2

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

so

A=(15^2)-(9^2)

A=225-81

A=144\ cm^2

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

A=\frac{1}{2}(b)(h)

where

b is the base of triangle

h is the height of triangle

so

A=\frac{1}{2}(6)(7)-(6)(2)

A=21-12

A=9\ m^2

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

A=\pi r^{2}

where

r is the radius of the circle

so

A=\pi (7^2)-(3)(11)

A=(49\pi -33)\ in^2

7 0
3 years ago
Identify the x-intercept
sveta [45]

im quite positive that the x-intercept is 1,6

8 0
2 years ago
Suppose Joe earned three times as much as Marty during the summer.Together they earned 210.How much did each earn?
JulijaS [17]

Answer:

Marty got 70 and then Joe earned 3 times it

Step-by-step explanation:


7 0
3 years ago
The function, f(x)=70n-400, models the profit of the instructor of a guitar class per month, where n is the number of students e
zimovet [89]

profit=f(x)

so solve for f(x)=1000

1000=70n-400

add 400 to both sides

1400=70n

divide both sides by 70

20=n

20 students need to be enrolled to make a profit of 1000.00

4 0
2 years ago
Find the mean of the following data set.<br> 42, 45, 58, 63<br> 42<br> 47<br> 52
igomit [66]
52 i believe.

42 + 45 + 58 + 63 = 208
208 / 4 = 52
6 0
3 years ago
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