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lora16 [44]
3 years ago
12

The lengths of the sides of the triangles are 13cm, 14cm, and 15cm. Is the triangle a right triangle?

Mathematics
1 answer:
natita [175]3 years ago
4 0

Answer:

no i don't think

Step-by-step explanation:

it is not be a right angle is 90 and when u add it it doesn't match

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If Mike has 96 muffins that needs to be boxed up into dozens and 6 of them are blueberry. How many boxes does he need?
ella [17]

Answer:

8 boxes

Step-by-step explanation:

x*12=96

x*12/12=96/12

x=8

7 0
3 years ago
Read 2 more answers
Is 4/5 a repeating decimal
Vitek1552 [10]

Answer:

No.

Step-by-step explanation:

4/5, when changed to a decimal, is a terminated decimal:

(4/5)(20/20) = 80/100 = 0.80

~

3 0
4 years ago
Evaluate the function at the given value and simplify.
Licemer1 [7]

Answer:

The correct option is b.

Step-by-step explanation:

The given function is

f(x)=-5x+1

We need to find the value of f(-2). It means we have to find the value of given function at x=-2.

Substitute x=-2 in the given function to find the value of f(-2).

f(-2)=-5(-2)+1

On simplification we get

f(-2)=10+1

f(-2)=11

The value of f(-2) is 11. Therefore the correct option is b.

8 0
3 years ago
In microbiology, colony-forming units (CFUs) are used to measure the number of microorganisms present in a sample. To determine
zimovet [89]

Answer:

(a)  0.2650

(b)  0.0111

(c)  0.0105

(d)  0.0006

Step-by-step explanation:

Given that:

In microbiology, colony-forming units (CFUs) are used to measure the number of microorganisms present in a sample.

Suppose that the number of CFUs that appear after incubation follows a Poisson distribution with mean μ = 15.       &;

If the area of the agar plate is 75cm²;

what is the probability  of observing fewer than 4 CFUs in a 25 cm² area of the plate.

We can determine the mean number of CFUs that appear on a 25cm² area of the plate as follows;

75cm²/25cm² = 3

Since;

mean  μ = 15  

mean number of CFUs that appear on a 25cm² = 15/3 = 5 CFUs

Thus ; the probability of observing fewer than 4 CFUs in a 25 cm² area of the plate is estimated as:

= P(X < 4)

Using the EXCEL FUNCTION ( = poisson.dist(3, 5, TRUE) )

we have ;

P(X < 4) = 0.2650

b) If you were to count the total number of CFUs in 5 plates, what is the probability you would observe more than 95 CFUs?

Given that the total number of CFUs = 5 plates; then the mean number of CFUs in 5 plates =  15×5 = 75 CFUs

The probability is therefore = P( X > 95 )

= 1 - P(X ≤ 95)

= 1 - poisson.dist(95,75,TRUE) ( by using the excel function)

= 0.0111

c) Repeat the probability calculation in part (b) but now use the normal approximation.

Let assume that the mean and the variance of the poisson distribution are equal

Then;

X \sim N (\mu = 75 , \sigma^2 = 75)

We are to repeated the probability calculation in part (b) from above;

So:

P( X > 95 )

use the normal approximation

From standard normal variable table:

P(Z > 2.3094)

Using normal table

P(Z > 2.3094) = 0.0105

(d)  Find the difference between this value and your answer in part (b).

So;

the difference between the value in part c and part b is;

=  0.0111 - 0.0105

= 6*10^{-4}

= 0.0006 to four decimal places

5 0
4 years ago
Someone help me please
natali 33 [55]
Part A:
1) 16
2) -25
3) 9
4) -7

I'm too lazy to do the rest, just pay attention in class next time
5 0
3 years ago
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