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sveticcg [70]
3 years ago
15

Find cos0, where 0 is the angle shown. Give an exact value, not a decimal approximation. (listing BRAINLEST)​

Mathematics
1 answer:
marshall27 [118]3 years ago
5 0

Step-by-step explanation:

everything can be found in the picture

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dexar [7]
X+ 10 = 26

-10 = -10

X = 16
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3 years ago
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Please Answer ASAP!!!
kirill115 [55]

Answer: g(1) is 1.

Step-by-step explanation:

If we are solving for g of 1  then the first equation can't be used to solve for g of 1 because it only works in x is equal to -2.

The same way the second function will not work because x has to equal to -1.

But in the last function which is written as a polynomial it will work for this situation because x is not equal to -2 or -1 so apart from those numbers every number will work the same way 1 will work.    

So plot 1 into the function and solve for it .

g(1) = 1^3 - 1^2 + 1  

g(1)=  1 - 1 + 1

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Answer:

do a line conforming to the table  days=x    sales =y

Step-by-step explanation:

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3 years ago
The heights of a certain population of corn plants follow a normal distribution with mean 145 cm and stan- dard deviation 22 cm
Firdavs [7]

Answer with explanation:

Given : The heights of a certain population of corn plants follow a normal distribution with mean \mu=145\ cm and standard deviation \sigma=22\ cm

a) Using formula z=\dfrac{x-\mu}{\sigma}, the z-value corresponds to x= 135 will be

z=\dfrac{135-145}{22}\approx-0.45

At x= 155, z=\dfrac{155-145}{22}\approx0.45

The probability that plants are between 135 and 155 cm tall :-

P(-0.45

Hence, 34.73% of the plants are between 135 and 155 cm tall.

b) Sample size : n= 16

Using formula z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}, the z-value corresponds to x= 135 will be

z=\dfrac{135-145}{22}{\sqrt{16}}\approx-1.82

At x= 155, z=\dfrac{155-145}{22}{\sqrt{16}}\approx1.82

The probability that plants are between 135 and 155 cm tall :-

P(-1.82

Hence,The percentage of the samples would the sample mean height be between 135 and 155 cm.= 93.12%  

4 0
3 years ago
The students at a school assembly were divided into 4 equal groups. There were 63 students in each group. Write and solve an equ
yuradex [85]

x  \div 4 = 63 \\  \frac{1}{4} x = 63 \\ x =  \frac{63}{ \frac{1}{4} }  = 252
hope this helps
4 0
4 years ago
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