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12345 [234]
2 years ago
7

Which side lengths form a right triangle?

Mathematics
1 answer:
tresset_1 [31]2 years ago
7 0

its q and c c c c c c c c c c c a a a a a a a a a a. a

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Mia has $132 in her bank account. She wants to buy a gucci bag, But, it costs 1,000 dollars. So, she sells her makeup, since she
stealth61 [152]

Answer: 1191 .00

Step-by-step explanation: well try this

1323 -132 = 1191

3 0
2 years ago
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HELPPPP PLEASEEE IM BEGGING SOMEONE PLEASE PLEASE HELP
pychu [463]

Given:

The figure of a rhombus QRST.

To find:

A. The value of x.

B. The measure of angle RQP.

Solution:

A. We need to find the value of x.

We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.

m\angle RPS=90^\circ                       [Right angle]

(5x+15)^\circ=90^\circ

(5x+15)=90

5x=90-15

5x=75

Divide both sides by 5.

x=\dfrac{75}{5}

x=15

Therefore, the value of x is 15.

B. We need to find the measure of angle RQP.

From the given figure, it is clear that

m\angle RQP=(2x+3)^\circ

Putting x=15, we get

m\angle RQP=(2(15)+3)^\circ

m\angle RQP=(30+3)^\circ

m\angle RQP=33^\circ

Therefore, the measure of angle RQP is 33 degrees.

8 0
2 years ago
Find the coordinates of the midpoint of the segment with endpoints A(-5, 6) and B(3, 2). You must show all work in order to rece
OLga [1]
Midpoint Formula = M = ( \frac{ x_{1}+x_{2}}{2}) + ( \frac{ y_{1} + y_{2}} {2})

We are given the coordinates: A(-5,6) and B(3,2)
Plug the values into the equation to get:
M = ((3 - 5)/2, (2 + 6)/2)
Now, just solve it down to get M = (-1,4).

The midpoint of the segment with endpoints A(-5,6) and B (3,2) is (-1,4). Hope this helps ALot and have a wonderful day!
4 0
3 years ago
Help this is due in 10 minutes
lilavasa [31]

Answer:

WHat do we help with?

Step-by-step explanation:

5 0
3 years ago
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An object moves along a coordinate axis so that its position at time t is given by s(t)=t3. Estimate its instantaneous velocity
Mademuasel [1]

If the position at time <em>t</em> is

<em>s(t)</em> = (1 m/s³) <em>t</em> ³

then the average velocity over <em>t</em> = 2 s and <em>t</em> = 2.001 s is

<em>v</em> (ave) = (<em>s</em> (2.001 s) - <em>s</em> (2 s)) / (2.001 s - 2 s)

<em>v</em> (ave) = ((1 m/s³) (2.001 s)³ - (1 m/s³) (2 s)³) / (2.001 s - 2 s)

<em>v</em> (ave) ≈ (8.01201 m - 8 m) / (0.001 s)

<em>v</em> (ave) ≈ 12.006 m/s

6 0
2 years ago
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