Answer:
I assume you know Arithmetic Progression .
so, we have to find the first and last 4-digit number divisible by 5
first = 1000 , last = 9990
we have a formula,
= a + (n-1)d
here,
is the last 4-digit number divisible by 5.
n is the number of 4-digit even numbers divisible by 5
d is the common difference between the numbers, which is 10 in this case
a is the first 4-digit number divisible by 5
9990 = 1000 + (n-1)*10
899 = n-1
n = 900
Hence, there are 900 4-digit even numbers divisible by 5
Answer:
1,800, 19
Step-by-step explanation:
102,619÷57=1800 (nearest one)
102,619-1800×57=19
Answer:
k = 6
Step-by-step explanation:
14k=84
k = 84/14
k = 6
to check the equation:
14k ..we found that k is 6, so replace k with 6
14(6)
84 ......checked.
Answer: 4.45 divided by 2 is 2.225
Answer:
81
Step-by-step explanation:
just do it step by step adding them together.