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Tresset [83]
3 years ago
7

Which results only in a horizontal compression of y=1/x by a factor of 6

Mathematics
2 answers:
yan [13]3 years ago
7 0

we are given

parent function as

y=\frac{1}{x}

Suppose, we are given a function y=f(x) is compressed horizontally by ''b'' units

where b>1

so, we can write as

new function as

y=f(bx)

Here, it is compressed by factor 6

so, we can replace x as 6x

and we get

y=\frac{1}{6x}

so, option-A.........Answer

dedylja [7]3 years ago
3 0

Answer:  A.  Y=\dfrac{1}{6x}

Step-by-step explanation:

When a graph with a function g(x) is horizontal compressed by a scale factor of k>1, then the new function of the compressed graph becomes :_

G(x)=g(kx)

Given function : y=\dfrac{1}{x}

Let  y=f(x)

When is is compressed by a scale factor of 6 , then the new function will become to represent the compressed graph:_

Y=f(6x)=\dfrac{1}{6x}

Hence, A is the CORRECT answer.

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28v^3+16v^2-21v-12 factor by group please
Mariana [72]
<h2> The factor of 28v^3+16v^2-21v-12 = (7v+4)(2v+\sqrt{3})(2v+\sqrt{3}) or (7v+4)(4v^2-3)</h2>

Step-by-step explanation:

The given equation:

28v^3+16v^2-21v-12

To find, the factors of 28v^3+16v^2-21v-12 = ?

∴ 28v^3+16v^2-21v-12

=(4\times 7)v^3+(4\times 4)v^2-(3\times 7)v-(3\times 4)

= 4v^2(7v+4)-3(7v+4)

= (7v+4)(4v^2-3)

= (7v+4)[(2v)^2-\sqrt{3}^2]

Using the algebraic identity,

a^{2}-b^{2}=(a+b)(a-b)

= (7v+4)(2v+\sqrt{3})(2v+\sqrt{3})

∴ The factor of 28v^3+16v^2-21v-12 = (7v+4)(2v+\sqrt{3})(2v+\sqrt{3}) or (7v+4)(4v^2-3)

7 0
3 years ago
ANSWER QUICK!
GREYUIT [131]
The actual answer is 5.66666666
The reason is that because he made 238 over 42 months you divide 238$ by 42 months
5 0
3 years ago
Denny lives in Maryland and pay 6% in sales tax. He just bought $145 in groceries, but $70 worth of those groceries were non tax
SpyIntel [72]

the answer should $201.25

6 0
3 years ago
Read 2 more answers
A 46 gram sample of a substance that is used to sterilize surgical instruments has a k-value of 0.1374. Find the substance's hal
mars1129 [50]

Answer:

  t=5.0days

Step-by-step explanation:

Using the formula for the exponential decay that is N=N_{0}e^{-kt}, we have N=\frac{1}{2}{\times}46=23, N_{0}=46 and k=0.1374.

Thus, N=N_{0}e^{-kt} becomes

23=46{\times}e^{-0.1374t}

\frac{23}{46}=e^{-0.1374t}

\frac{1}{2}=e^{-0.1374t}

Taking log on both sides, we get

ln(\frac{1}{2})={-0.1374t}

t=\frac{ln\frac{1}{2}}{-0.1}

t=\frac{-0.6931}{-0.1374}

t=5.0days

4 0
3 years ago
Need help with number 60
vampirchik [111]
You could write 42/20 for #60.
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