Answer:
(3 ± √23 * i) /4
Step-by-step explanation:
To solve this, we can apply the Quadratic Equation.
In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)
Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4
Plugging these values into our equation, we get
x = (-b ± √(b²-4ac))/(2a)
x = (-(-3) ± √(3²-4(2)(4)))/(2(2))
= (3 ± √(9-32))/4
= (3 ± √(-23))/4
= (3 ± √23 * i) /4
They all only have 1 term.
Answer:
20/81
Step-by-step explanation:
Without parentheses, it is hard to tell what you are dividing. We assume you want ...
(4/9)/(9/5)
Then ...
_____
As written (without parentheses), your expression is evaluated left to right, so evaluates to ...
4/(9·9·5) = 4/405
30/5= 6
6 - 2 = 4
Your number is four
Answer:
I need sum more detail to answer just email me and we can get this dun.
Step-by-step explanation:
