Pls help with the right answer pls thx :D. Find m

Which polynomial expression represents a sum of cubes? (6 – s)(s2 + 6s + 36) (6 + s)(s2 – 6s – 36) (6 + s)(s2 – 6s + 36) (6 + s)

Nadusha1986 [10]

Answer:

Option 3 is correct that is $(6+s)(s^2-6s+36)$

Step-by-step explanation:

We have general formula for sum of cube which is

$a^3+b^3=(a+b)(a^2+b^2-ab)$

Here, we have a=s and b=6

on substituting the values in the formula we will get

$6^3+s^3=(6+s)(s^2+6^2-6s)$

After simplification we will get

$6^3+s^3=(6+s)(s^2+36-6s)$

After rearranging the terms we will get

$6^3+s^3=(6+s)(s^2-6s+36)$ which exactly matches option 3 in the given options.

Therefore, option 3 is correct that is $(6+s)(s^2-6s+36)$

4 0

4 years ago

Read 2 more answers

Given the graph below, find the slope. A. -3/2 B.3/2 C -2/3 D. 2/3

Irina18 [472]

The answer is or the slope is D 2/3

8 0

3 years ago

A digital scale reports a 10kg weight as weighing 8.975kg. which of the following is true?

lukranit [14]

That question is accompanied by these answer choices:

A. The scale is accurate but not precise.
B. The scale is precise but not accurate.
C. The scale is neither precise nor accurate.
D. The scale is both accurate and precise.

Then you need to distinguish between accuracy and precision.

Accuracy refers to the closeness of the measure to the real value, while precision, in this case, refers to the level of significant figures that the sacle report.

The fact that the scale reports the number with 4 significant figures means that it is very precise, but the fact that the result is not so close to the real value as the number of significan figures pretend to be, means that the scale is not accurate.

So, the answer is that the scale is precise but not accurate (the option B).

6 0

3 years ago

What is the sale price of this bed after the discount has been taken off the standard price?

vladimir2022 [97]

Answer:

585 is the answer of your question.

Step-by-step explanation:

because formula is

Mp _ d% of mp

4 0

3 years ago

Read 2 more answers

21 Maria sold small boxes of candy for $1 and

Anna35 [415]

Answer:

There where 10 more Small boxes sold than Large boxes.

Step-by-step explanation:

This is a typical question that can be solved by obtaining a system of two linear equations and solving for each variable.

In principle Linear Equations are algebraic expressions denoting a relationship between a Dependent variable $y$ and an Independent variable $x$ . In a system of Two Linear equations we have two equations of the same variable sets (thus Two Independent variables) so in this case both $y$ and $x$ will be variable terms.

Now with respect to the question and the given information, here our two Variable terms will be the small and the large boxes.

Given Information:

Small Boxes (lets call them $s$ ) cost $1 per box

Large Boxes (lets call them $l$ ) cost $4 per box
Total Number of Boxes sold is 30
Total Profit from sold Boxes is $60

Thus from the above we can obtain one equation denoting the Total Number of Boxes sold and one equation denoting the Total Profit from sold boxes, respectively, as follow:

$s+l=30$ Eqn(1): Total Number of Boxes

$1s+4l=60$ Eqn(2): Total Profit from sold boxes

Now we have a system of two linear equations which we can solve and find the number of small and large boxes, $s$ and $l$ respectively.

From Eqn(1) we see that

$s=30-l$ Eqn(3).

Plugging Eqn(3) in Eqn(2) we can solve for $l$ as:

$1(30-l)+4l=60$

$30-l+4l=60$ Factored out bracket

$3l=60-30$ Gather similar terms on each side and simplify

$3l=30$

$l=\frac{30}{3}$

$l=10$

Plugging in the value for $l=10$ in Eqn(3) we have

$s=30-10\\s=20$

So we know that they were 10 Large Boxes and 20 Small Boxes sold, thus to answer our question, there where 10 more Small boxes sold than Large boxes.

5 0

4 years ago