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Nata [24]
3 years ago
6

Pls help with the right answer pls thx :D. Find m

Mathematics
1 answer:
prisoha [69]3 years ago
3 0

Answer:

where is the question

Step-by-step explanation:

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The quotient of (x^3+3x^2-4x-12)/(x^2+5x+6)
Elis [28]

Answer: The quotient is (x-2).

Step-by-step explanation:

Since we have given that

f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}

Now, we have to find the quotient of the above expression.

So, here we go:

Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)

Now, we will divide the above simplest form with g(x):

\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2

Hence, the quotient is (x-2).


6 0
3 years ago
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When dividing 39100 by 100 the digits in the quotient will move how many places to the right
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I need help i'm really still confused on the Tan thing in algebra
AysviL [449]

Answer:6/8

Step-by-step explanation:

4 0
3 years ago
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What would my grade be if i had a 76% in the class, then got a 0% on a test worth 70% of my grade?
ExtremeBDS [4]

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I believe it would be 6

7 0
3 years ago
Mathematics
Vladimir [108]

Answer:

there no data

Step-by-step explanation:

Find the median of the first and third quartiles81, 69 ,90, 79, 59, 125, 95, 116, 183, 97, 92, 50, 122, 55, 9250, 55, 59, 69, 79, 81, 90,   92,     92, 95, 97, 116, 122, 125, 183.The first quartile: 50, 55, 59, 69, 79, 81, 90: median of the first quartile is 69The third quartile: 92, 95, 97, 116, 122, 125, 183: median of the third quartile is 116.The interquartile range is the difference between the median of both the first and third quartile:  which is 116 - 69 = 47.There are no outliers in this set of data

4 0
1 year ago
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